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2 years ago

A pound is equal to 0.454 kilograms, how many kilograms does a 142-pound man weigh

Mathematics

2 answers:

levacccp [35]2 years ago

5 0

Answer:

64.468

Step-by-step explanation:

myrzilka [38]2 years ago

4 0

Answer: 64.468 kilograms

Step-by-step explanation:

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Fill in the missing number to make the sentence true ?/6 < 1/2

Ira Lisetskai [31]

Answer:

1 or 2

Step-by-step explanation:

1/6 < 1/2 (because 1/2 = 3/6 and 1/6 < 3/6)

2/6 < 1/2 (because 2/6 = 1/3 and if we convert these numbers to decimals, then 0.33 [2/6] < 0.5 [1/2])

8 0

3 years ago

Autos de F 1. En un circuito de Australia, Hamilton hizo el récord de vuelta. Si lo normal a 240km/h para completar el circuito

olga2289 [7]

Answer:

Tenía que hacerlo en menos de 2 minutos a más de 240 km/h

Step-by-step explanation:

La velocidad normal dada para completar el circuito de 6.000 metros = 240 km/h

El tiempo normal que se tarda en completar el circuito de 6000 metros = 2 minutos

Dado que Hamilton estableció el récord de vuelta, el tiempo que tuvo que hacer para recorrer el récord de vuelta es de 6000 metros en menos de 2 minutos

La velocidad media con la que lo hizo es de más de 240 km/h.

6 0

2 years ago

I need help please<br><br> I need help please<br><br> I need help please

harina [27]

Answer:

0,0 which is the origin.

7 0

1 year ago

Solving Rational Functions Hello I'm posting again because I really need help on this any help is appreciated!!

Greeley [361]

Answer:

x = √17 and x = -√17

Step-by-step explanation:

We have the equation:

$\frac{3}{x + 4} - \frac{1}{x + 3} = \frac{x + 9}{(x^2 + 7x + 12)}$

To solve this we need to remove the denominators.

Then we can first multiply both sides by (x + 4) to get:

$\frac{3*(x + 4)}{x + 4} - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

$3 - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x + 3)

$3*(x + 3) - \frac{(x + 4)*(x+3)}{x + 3} = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$3*(x + 3) - (x + 4) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$(2*x + 5) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x^2 + 7*x + 12)

$(2*x + 5)*(x^2 + 7x + 12) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}*(x^2 + 7x + 12)$

$(2*x + 5)*(x^2 + 7x + 12) = (x + 9)*(x + 4)*(x+3)$

Now we need to solve this:

we will get

$2*x^3 + 19*x^2 + 59*x + 60 = (x^2 + 13*x + 3)*(x + 3)$

$2*x^3 + 19*x^2 + 59*x + 60 = x^3 + 16*x^2 + 42*x + 9$

Then we get:

$2*x^3 + 19*x^2 + 59*x + 60 - ( x^3 + 16*x^2 + 42*x + 9) = 0$

$x^3 + 3x^2 + 17*x + 51 = 0$

So now we only need to solve this.

We can see that the constant is 51.

Then one root will be a factor of 51.

The factors of -51 are:

-3 and -17

Let's try -3

p( -3) = (-3)^3 + 3*(-3)^2 + +17*(-3) + 51 = 0

Then x = -3 is one solution of the equation.

But if we look at the original equation, x = -3 will lead to a zero in one denominator, then this solution can be ignored.

This means that we can take a factor (x + 3) out, so we can rewrite our equation as:

$x^3 + 3x^2 + 17*x + 51 = (x + 3)*(x^2 + 17) = 0$

The other two solutions are when the other term is equal to zero.

Then the other two solutions are given by:

x = ±√17

And neither of these have problems in the denominators, so we can conclude that the solutions are:

x = √17 and x = -√17

6 0

2 years ago

2) The two rectangles shown are similar.

Citrus2011 [14]

Answer:

$6\ cm$

Step-by-step explanation:

First Rectangle:

$length(l_1)=24\ cm\\\\Width(b_1)=9\ cm$

Second Rectangle:

$length(l_2)=16\ cm\\\\Let\ Width=b_2\ cm$

$Since\ these\ two\ rectangles\ are\ similar\\\\\frac{l_2}{l_1}=\frac{b_2}{b_1}\\\\\frac{16}{24}=\frac{b_2}{9}\\\\16\times 9=24\times b_2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ cross\ multiplication\\\\b_2=\frac{16\times 9}{24}\\\\b_2=6\ cm$

5 0

3 years ago