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brilliants [131]
3 years ago
6

Could you please help me out ?

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
3 0
1. The sum of the interior angles of a triangle is 180º, so we have:
 
 m∠K= 180º-58º-38º
 m∠K= 84º 
 
 2. If we draw a perpendicular segment from "K" to "k", we will obtain two right triangles and we can find the value of "k".
 
 3. Let's find the heigh ot these two triangles (The perpendicular segment from "K" to "k", which we will call "y"):
 
 Sen(α)=Opposite leg/Hypotenuse
 Sen(58º)=y/2.3
 y=2.3xSen(58º)
 y=1.95 units
 
 4. Now we must find the adjacent leg of the triangle on the left:
 
 Cos(α)=Adjacent leg/Hypotenuse
 Cos(58º)=Adjacent leg/2.3
 Adjacent leg=1.21 units
 
 5. Let's find the adjacent leg of the other triangle:
 
 Tan(38º)=Opposite leg/Adjacent leg
 Adjacent leg=2.49 units
 
 6. The lenght of "k" is:
 
 k=2.49 units+1.21 units
 k=3.7 units
 
 7. The length KL is:
 
 Cos(38º)=Adjacent leg/Hypotenuse
 Cos(38º)=2.49/KL
 KL=2.49/Cos(38º)
 KL=3.15 units
 KL≈3.2 units
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Answer: 150mm

Step-by-step explanation:

Take the two adjecent sides of the triangle to be x and y and X is the angle opposite the side, x.

From the trigonometric identities for a right-angled triangle, it is known that

x=170sin X and;

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Thus the perimeter of the triangle is given by

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170(sin X + cos X) = 400 - 170

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Squaring both sides hence,

sin^2(X) + 2sin X.cos X + cos^2(X) = 1.8304

Recall that sin^2(X) + cos^2(X) = 1 and 2sin X.cos X = sin 2X.

Thus, the former expression gives;

1 + sin 2X = 1.8304

sin 2X = 0.8304

2X = arcsin (0.8304)

2X = 56.14° or (180 - 56.14)° = 56.14° or 123.86° for X existing within a triangle.

X = 56.14/2 or 123.86/2

X = 28.07° or 61.93°

Thus the two adjacent sides are ;

x = 170 sin (28.07) = 80mm

y = 170 cos (28.07) = 150mm

Using the value of 61.93° as X would give the same values but interchanged for x and y.

I hope you find this useful.

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