Solve using elimination PLEASE I NEED HELP!!! IT WOULD REALLY MEAN A LOT IF ANYONE CAN ANSWER THIS! 16 POINTS!!!

Mathematics

1 answer:

Marysya12 [62]3 years ago

4 0

Answer:

(x, y) = (2, -3/4)

Step-by-step explanation:

The point of the "elimination" technique is to combine the equations in a way that eliminates one of the variables. Sometimes this involves multiplying one or both of the equations by constants before you add those results together. In any event, the first step is to look at the coefficients of the variable terms to see if there is a simple combination of them that will result in zero.

The y terms have coefficients that are opposites of each other (4, -4), so you can simply add the two equations to eliminate y as a variable.

(2x +4y) +(x -4y) = (1) +(5)

3x = 6 . . . . . simplify

x = 2 . . . . . . divide by 3

Now, you find y by substituting this value into one of the equations. I would choose the equation with the positive y-coefficient:

2(2) +4y = 1

4y = -3 . . . . . . subtract 4

y = -3/4

Then the solution is ...

(x, y) = (2, -3/4)

_____

A graphing calculator confirms this solution.

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Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10

AnnyKZ [126]

Answer:

a)P=0.42

b) $n\geq 297$

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

$P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}$

a) we have k=2, n=10 and p=0.01:

$P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42$

b) We have, $1-(1-p)^n=P$ , Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.