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Alona [7]
3 years ago
5

Find the coordinates of the image after a reflection across y=-1 followed by a translation <2,-1>.

Mathematics
1 answer:
tiny-mole [99]3 years ago
5 0

Answer:

S' (1,-2)

S'' (0,0)

Step-by-step explanation:

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What is (-2,6) and ( 5,13) in slope
Feliz [49]

rise / run

13 + 6 / - 2 + 5 = 19 / - 3 = - 6.333 or - 6 and 1 / 3

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A baseball team has won 10 of its first 18 games.There were no ties.Select three sets of games won games lost that are proportio
storchak [24]

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idk but my guess is d

Step-by-step explanation:

7 0
3 years ago
Farah rolls a fair dice and flips a fair coin. What is the probability of obtaining a 5 and a head? Give your answer in its simp
yan [13]

Answer:

1/12

Step-by-step explanation:

1 in 6 probablity on the dice and 1/2 probablity on the coin. multiply 6 and 2 = 12

1/12 probablity

i think this is the right answer but im not 100 percent sure

6 0
3 years ago
The graph of which function will contain the point(2,10)​
kotegsom [21]

Answer:

point (2 , 10)

Y= 5X

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3 0
2 years ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
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