There are 3
exclusive mutually birth orders that could
make two
affecteds and 1 unaffected - unaffected child first born, unaffected child
second born,
and unaffected child third born. Thus, there is a 3/64 + 3/64 + 3/64
= 9/64
chance that 2 out of 3 children will be affected.
Brown algae and dinoflagellates
Reason: Because they are the closest being in the same branch, makes them the most related.
Hope this helps! :))
Tar sands pits , sorry if I got this wrong
In cell biology, mitosis (/maɪˈtoʊsɪs/) is a part of the cell cycle in which replicated chromosomes are separated into two new nuclei. Cell division gives rise to genetically identical cells in which the total number of chromosomes is maintained. Therefore, mitosis is also known as equational division. In general, mitosis is preceded by S phase of interphase (during which DNA replication occurs) and is often followed by telophase and cytokinesis; which divides the cytoplasm, organelles and cell membrane of one cell into two new cells containing roughly equal shares of these cellular components. The different stages of mitosis altogether define the mitotic (M) phase of an animal cell cycle—the division of the mother cell into two daughter cells genetically identical to each other. So yes i would put A-Mitosis
Closed intranuclear pleuromitosis is typical of Foraminifera, some Prasinomonadida, some Kinetoplastida, the Oxymonadida, the Haplosporidia, many fungi ( chytrids, oomycetes, zygomycetes, ascomycetes ), and some Radiolaria ( Spumellaria and Acantharia ...
Closed extranuclear pleuromitosis occurs in Trichomonadida and Dinoflagellata.
Closed orthomitosis is found among diatoms, ciliates, some Microsporidia, unicellular yeasts and some multicellular fungi.
Semiopen pleuromitosis is typical of most Apicomplexa.
Semiopen orthomitosis occurs with different variants in some amoebae ( Lobosa) and some green flagellates (e.g., Raphidophyta or Volvox ).
1. Moles Fe = 209.7 g/ 55.847 g/mol= 3.75
The ratio between Fe and CO is 2 : 3
Moles CO = 3.75 x 3 /2 = 5.63
<span>Mass CO = 5.63 mol x 28.01 g/mol= 157.7 g
2. </span><span />2Na + 2H2O --> 2NaOH + H2<span>atomic weight of sodium is 23 48.7/23 = 2.12 moles of sodium
2.12/2 x 24 = 25.44dm^3 hydrogen = 1.06 moles
so multiply it by Avogadro's number1.06 X 6.02x10^23 = 1.204x10^24 molecules of hydrogen
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