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4 years ago

Evaluate ∫ cot 2x dx.

1 answer:

3 0

∫ cot 2x dx=
 ∫ ((cos (2x))/(sen(2x)) dx
u=sen(2x)
du=2cos(2x)dx
∫ ((1/2)*(1/u))du=
(1/2)*Ln(u) + C
(1/2)*Ln(sen(2x)) + C
answer
 C. ½ Ln sin 2x + C

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