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3 years ago

Which resources provides an opportunity to evaluate your readiness for a major assessment?

1 answer:

7 0

B. TEcher tutorial is the answer I believe because it makes since it helps evaluate your readiness for a major assessment

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Turn 54.1256 into a fraction

mel-nik [20]

I get 433 divided by 8 .... 433/8

3 0

3 years ago

Read 2 more answers

To create a unique house paint color, Melton mixes together a sample that is 12 gallons of red, 2.5 gallons of yellow and 0.5 ga

Mariana [72]

Answer:

180

Step-by-step explanation:

total ratio is 15

gallons of red =

$\frac{12}{15} \times 6 \times \frac{15}{0.5 } \\ \\ = 144$

gallons of yellow

$30$

gallons of blue

$\frac{0.5}{15} \times 30 \times \frac{15}{2.5} \\ \\ = 6$

total =144+30+6

=180

4 0

2 years ago

Read 2 more answers

Currently, an employee can assemble on average, x amount of masks per hour. An INDLS student makes twice as many N95 Masks as th

PtichkaEL [24]

The correct answers is 45 masks per hour

8 0

3 years ago

What is the angle measure of an arc bounding sector with an area of 5pie square miles?

Snowcat [4.5K]

if the diameter is 20, the its radius must be half that or 10.

$\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ A=5\pi \\ r=10 \end{cases}\implies \begin{array}{llll} 5\pi =\cfrac{\theta \pi (10)^2}{360}\implies 5\pi =\cfrac{5\pi \theta }{18} \\\\\\ \cfrac{5\pi }{5\pi }=\cfrac{\theta }{18}\implies 1=\cfrac{\theta }{18}\implies 18=\theta \end{array}$

8 0

2 years ago

Rewrite the system of linear equations as a matrix equation AX = B.

iren2701 [21]

Answer:

$\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]$

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

$\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]$

And the vector of vriables (X) is:

$\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]$

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

$\left[\begin{array}{ccc}5\\6\\7\end{array}\right]$

In conclusion, AX=B is:

$\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]$

7 0

3 years ago