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2 years ago

Which resources provides an opportunity to evaluate your readiness for a major assessment?

1 answer:

7 0

B. TEcher tutorial is the answer I believe because it makes since it helps evaluate your readiness for a major assessment

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Can someone help me? It's urgent and thank you!

nordsb [41]

Answer:

the first one

Step-by-step explanation:

3 0

2 years ago

Use distributive property to simplify (0.32x+5.3)+(0.5x+5.6)+(0.03x+0.2)

Serhud [2]

the answer is

.85x+11.1

6 0

3 years ago

Read 2 more answers

1. 2 4/5v-2/3(4v+1 1/6)

Lerok [7]

1. -48v-5/45 2.44-r/2 3. x=2

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2 years ago

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Find the measure of arc DB in P<br><br>please hurry if you can

jeyben [28]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:m\overbrace{DB}= 90 \degree$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: m \overbrace{DB} + m \overbrace{TB} = 180 \degree$

[ linear pair ]

$\qquad \tt \rightarrow \: m \overbrace{DB} + 90 \degree = 180 \degree$

$\qquad \tt \rightarrow \: m \overbrace{DB} = 180 \degree - 90 \degree$

$\qquad \tt \rightarrow \: m \overbrace{DB} = 90 \degree$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0

1 year ago

A light bulb factory produces 922 light bulbs every hour. Approximately 3.34% of the light bulbs are defective, and do not work.

Nikitich [7]

Answer:

The value is $\sigma = 5.46$

Step-by-step explanation:

From the question we are told that

The number of light produced in an hour is n = 922

The proportion of the bulb that are defective is p = 0.0334

Generally given from the question that we should use binomial distribution it then means that the standard deviation is mathematically evaluated as

$\sigma = \sqrt{ n * p (1-p)}$

=> $\sigma = \sqrt{ 922 * 0.0334 * (1-0.0334)}$

=> $\sigma = 5.46$

8 0

2 years ago