Answer:
a perfect square because 17 x 17 = 289
It's not a perfect cube
Step-by-step explanation:
Answer:
(a) 74553
(b) 172120
(c) 234802
Step-by-step explanation:
Given

Solving (a): 1998
Year 1998 means that:


So, we have:




--- approximated
Solving (b): 2003
Year 2003 means that:


So, we have:




--- approximated
Solving (c): 2006
Year 2006 means that:


So, we have:




--- approximated
Answer:
12+36p
Step-by-step explanation:
First distribute the 2 to binomial then the 6.
6(2+6p)
12+36p
Answer:
<h2>B. The amount of fuel used was lowest at speeds around 60km/h.</h2>
Step-by-step explanation:
The decreasing part is from (20,13) to (60,6), which gives an average rate of

Then, we have an increasing part from (60,6) to (120,10), which gives an average rate of

Basically, at 60 km/h the fuel used was 6 liters per 100 kilometers. Notice that the other velocities make the car to use more liters per kilometers.
Therefore, the amount of fuel used was lowest at speeds around 60 km/h.
Answer: C
Step-by-step explanation: c is the correct answer. A is incorrect, because 8 is subtracting t, so it is a higher value. B is incorrect because it’s 8/f so 8 is greater. (If it was f/8 then 8 would be less). C is correct because 8 is being taken away from f, not the other way around. And lastly, d is incorrect bc there’s no way to tell which is greater/less. Hope this helped ;)