Question

Question 3 and 4 please!

Answer 1

Question 3:

1. $f(x)=(\frac{2}{3})x^2+3x-2$⇒standard form
2. $f(x)=3x^2-8x+5(3x-8)$⇒intercept form
3. $f(x)=4(x-5)^2+20$⇒ vertex form
4. $f(x)=-(3x-8)(3x+5)$⇒none of the above

Question 4:Explain in detail how to solve the following function by completing the square:

$x^2+8x-9=0$

1. move the term to left side (done)

$x^2+8x-9=0$

2. use the quadratic formula

$x=\frac{-b+\sqrt{b^2-4ac} }{2a}$

A=1

B=8

C=-9

$x=\frac{-(8)+\sqrt{(8)^2-4(1)(-9)} }{2(1)}$

x=1

now check your answer.

1^2+8(1)-9=0