The simple way of calculating a perimeter is to add all of the sides.
For a rectangle this would equal 2 x length + 2 x width
P = 2(6x + 3) + 2(-2x - 5)
= 12x + 6 - 4x - 10
= 8x - 4
At a higher level both the length and width must be greater than zero (= zero is a trivial rectangle)
6x + 3 > 0
6x > -3
x > -0.5
-2x - 5 > 0
2x + 5 < 0 (multiplying by -1 reverses the inequality)
2x < -5
x < -2.5
This rectangle cannot exist as x cannot be < -2.5 and > -0.5 at the same time!
Hello,
y=2x+5
==========
(y-5)=2(x-0)
See the picture attached to better understand the problem
we know that
in the right triangle ABC
cos A=AC/AB
cos A=1/3
so
1/3=AC/AB----->AB=3*AC-----> square----> AB²=9*AC²----> equation 1
applying the Pythagoras Theorem
BC²+AC²=AB²-----> 2²+AC²=AB²---> 4+AC²=AB²----> equation 2
substitute equation 1 in equation 2
4+AC²=9*AC²----> 8*AC²=4----> AC²=1/2----> AC=√2/2
so
AB²=9*AC²----> AB²=9*(√2/2)²----> AB=(3√2)/2
the answer isthe hypotenuse is (3√2)/2
Answer:
x = 7
Step by step explanation:
<em>minus</em><em> </em><em>x</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em>
6 = x -1
<em>add</em><em> </em><em>1</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em>
<em>x</em><em> </em><em>=</em><em> </em><em>7</em>
Step-by-step explanation:
x -0.1x = x(1-0.1) = 0.9x