Answer:
The limiting reactant is the K
Explanation:
This is the reaction:
2 K + F₂ → 2KF
2 moles of potassium react with 1 mol of fluorine
Let's determine the moles:
6.02x10²³ molecules are contained in 1 mol
10 molecules are contained in (10 . 1) / NA = 1.66x10⁻²³ moles
For 1 mol of flourine, we need 2 moles of K
If we have 1.66x10⁻²³ moles of Fl₂, we will need the double of K
For 2 moles of K, we need 1 mol of Fl₂
If we have 1.66x10⁻²³ moles of K, we will need the half of Fl₂
Then, the limiting reactant is the K
