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2 years ago

How does overvoltage influence the products in the electrolysis of aqueous salts?

1 answer:

7 0

Overvoltage influence the products in the electrolysis of aqueous salts by affecting the solvation effects, polarization of electrode, and also affect the formation of gaseous products.

<h3>What is electrolysis? </h3>

It is defined as a process which leads to the chemical change when an electric current is allow to pass through an electrolyte.

During the electrolysis process,the positively charged electrode gains the electrons and undergoes the reduction process while the negatively charged electrode loses the electrons , undergoes oxidation.

When two half reaction are possible at an electrode, one with the other which is more positive electrode potential occur. For the gases to be produced at electrodes, an additional voltage is required. This is termed as overvoltage.

The overvoltage affects the solvation effects, polarization of electrode, and also affect the formation of gaseous products.

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How many litres of fluorine gas at stp can be collected from the decomposition of 90.7 g of AuF3

7nadin3 [17]

Answer: 12 L fluorine gas at STP can be collected from the decomposition of 90.7 g of $AuF_3$

Explanation:

The balanced decomposition reaction is shown as

$2AuF_3\rightarrow 2Au+3F_2$

moles of $AuF_3=\frac{\text {given mass}}{\text {Molar mass}}=\frac{90.7g}{254g/mol}=0.36moles$

According to stoichiometry:

2 moles of $AuF_3$ gives = 3 moles of flourine gas

Thus 0.36 moles of $AuF_3$ gives = $\frac{3}{2}\times 0.36=0.54moles$ of flourine gas

Using ideal gas equation :

$PV=nRT$

P = pressure of gas = 1 atm ( at STP)

V = Volume of gas = ?

n = moles of gas = 0.54

R = gas constant = 0.0821 L atm/Kmol

T = temperature = 273 K ( at STP)

Putting the values we get :

$1atm\times V=0.54mol\times 0.0821Latm/Kmol\times 273K$

$V=12L$

Thus 12 L fluorine gas at STP can be collected from the decomposition of 90.7 g of $AuF_3$

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