You are given the equation 36 = 9x² + 4y². You are asked to find the slopes of the asymptotes of the hyperbola. A hyperbola has the following general equation x²/a² + y²/b² = 1. the goal here is to find the slopes of the hyperbolic equation. So divide both sides by 36
36 = 9x² + 4y²
(1/36)[36 = 9x² + 4y²]
1 = x²/4 + y²/9
a² = 4
a = 2
and
b² = 9
b = 3
To find the slope, divide a/b and you will get 2/3.
Answer:
The perimeter is 22.
Step-by-step explanation:
The perimeter formula (it sometimes varies) is 2(b+h)
b being base (in this example, 6)
h being height (in this example, 5)
So now, with substitution, we are left with:
2(6+5)
Which simplifies down to:
2(11)
22
The common factor of 45 and 6 is 3
The common factor of
m and m^5 is m
Together the GCF is 3m
9514 1404 393
Answer:
BC = 5
Step-by-step explanation:
Of course, this geometry program can tell you the length of BC.
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If you follow directions, you get a right triangle BCF that has leg lengths 3 and 4. The Pythagorean theorem then tells you the length of hypotenuse BC is ...
BF = 4 -1 = 3
FC = 4 -0 = 4
BC² = BF² +FC²
BC² = 3² +4² = 9 +16 = 25
BC = √25
BC = 5
