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4 years ago

HHHHEEEEELLLLLPPPPPPP PLEASEEE ANSWER #1 AND #2

Mathematics

2 answers:

jek_recluse [69]4 years ago

7 0

Answer:

37=-3+5(k+6)

37=-3+5k+30

37=27+5k

37-27=5k

5k=10

k=10/2

k=5

***********************************************************************************

-2=-w+8

-2-8=-w

-w=-10

w=10

Vlad [161]4 years ago

3 0

Answer:

37 = -3 + 5(k +6)

37 = -3 + 5k + 30

37 = 27 + 5k

10 = 5k

k = 2

-2 = -(w - 8)

-2 = -w + 8

-10 = -w

w = 10

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sdas [7]

Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

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so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

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$\quad\quad 98a=-26$

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Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

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Rus_ich [418]

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