Ask question

Ask question

All categories

2 years ago

10

A swimming pool and deck are built in a rectangle with length 40 ft and width 18 ft. If the pool itself is 320 square feet, what

is the area of the deck itself?

1 answer:

stich3 [128]2 years ago

8 0

320x2=640
64u0x18=435
ugddx bb v

You might be interested in

A bike shop marks up a hybrid bike from $200 to $330 and discounts a road bike from 330 to 200 by what you percent is the road b

erik [133]

Answer:

39.39%

Step-by-step explanation:

There's a nice little formula that is used to find percentage change which works regardless of if it's an increase or decrease.

$Percent~Change = |\frac{New~Value~-~Original~Value}{Original~Value}| * 100$

1 - Understanding the equation

The '|'s which are surrounding the fraction are absolute value symbols in mathematics,

Absolute value means the positive value of anything inside

<u>Examples</u>:

| -8 | = 8

| 8 | = 8

and

| -2 | = 2

| 2 | = 2

the * 100 means you multiply (the * symbol means multiply) by 100.

We do this to get it into a percent.

3 - Assign numbers to the values from our equation

Original Value (What it changed from): 330

New Value (What it changed to): 200

3 - Plug in our values into our variables from our equation $Percent~Change = |\frac{200-330}{330}| * 100 = |\frac{-130}{330}| = = |-0.39...| * 100 = 0.3939... *100 =$

<em>Our percent change is 39.39%, and with our percent in which is discounted being the same, we have our answer.</em>

<em />

Hope this helps :)

7 0

3 years ago

IrinaVladis [17]

Answer:

18 seeds

Step-by-step explanation:

3 x 6 = 18 seeds

3/5 x 30 = 18 seeds

Hope that helps!

7 0

2 years ago

An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than

Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: $H_0: \mu \leq 10$

The alternative hypothesis is: $H_1: \mu > 10$

b)

The critical value is: $t_c = 1.74$

The decision rule is:

If t < 1.74, we <u>do not reject</u> the null hypothesis.
If t > 1.74, we <u>reject</u> the null hypothesis.

c)

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of <u>at most 10 pounds</u>, that is:

$H_0: \mu \leq 10$

At the alternative hypothesis, it is tested if the mean loss is of <u>more than 10 pounds</u>, that is:

$H_1: \mu > 10$

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a <u>significance level of 0.05</u> and 18 - 1 = <u>17 df.</u>

Hence, using a calculator for the t-distribution, the critical value is: $t_c = 1.74$ .

Hence, the decision rule is:

If t < 1.74, we <u>do not reject</u> the null hypothesis.
If t > 1.74, we <u>reject</u> the null hypothesis.

Item c:

We have the <u>standard deviation for the sample</u>, hence the t-distribution is used. The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

For this problem, we have that:

$\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18$

Thus, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}$

$t = 1.41$

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0

2 years ago

The length of time a particular smartphone's battery lasts follows an exponential distribution with a mean of ten months. A samp

aev [14]

Answer:

Probability between 7 and 11 is 0.7799

8 0

3 years ago

Solve for n. 2n − 35=52n − 35=5

melomori [17]

The answer is n= 35/2

7 0

2 years ago

Read 2 more answers