Consider this option:
1. given: n(A;B;C)=n(-5;-4;-1) and A(-1;-5;-2)=A(x₀;y₀;z₀).
Common view of equation for a plane is Ax+By+Cz+D=0, where A,B,C,D - numbers.
2. from another side using coordinates of A and normal vector it is possible to make up the equation: A(x-x₀)+B(y-y₀)+C(z-z₀)=0 ⇒ -5(x+1)-4(y+5)-(z+2)=0; ⇒ -5x-4y-z-27=0 or 5x+4y+z+27=0.
Answer:
I think the answer is C 0.83 based on the math I did
Step-by-step explanation:
Answer:
y≤x²+4x-1.
Step-by-step explanation:
1) to define the equation of the given graph; it is y=x²+4x-1 (its vertex is (-2;-5));
2) to define inequation accorging to the given graph (the area outside of the parabola means ≤).
See attachment for answer and math work.