Hey please help meeeeeeeeeeeeeeeee please do atleast 2 questions

Mathematics

1 answer:

Paraphin [41]2 years ago

5 0

Answer:

2. 88, 3. 40, 4. 48, 5. 20

Step-by-step explanation:

first multiply&divide, then calculate from left to right

2. 5 · 4² + (2 · 3 + 2) = 5 · 16 + 6 + 2 = 88

3. (4 + 3)² - 12 + 3 = 49 - 12 + 3 = 40

4. 64 ÷ 4 · 3 = 16 · 3 = 48

5. 3² - 4 + 5 · 3 = 9 - 4 + 15 = 20

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Find f(x) + g(x) when f(x) = 2x^2 + x and g(x) = 3x + 2

Artyom0805 [142]

Answer:

2x^2 + 4x+2

Step-by-step explanation:

f(x) = 2x^2 + x and g(x) = 3x + 2

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Combine like terms

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3 years ago

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It has a time to failure distribution which is normal with a mean of 35,000 vehicle miles and a standard deviation of 7,000 vehi

Triss [41]

Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that $\mu = 35000, \sigma = 7000$

Find its designed life if a .97 reliability is desired.

The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

$Z = \frac{X - \mu}{\sigma}$

$-1.88 = \frac{X - 35000}{7000}$