What is the difference? 4/3-7/9
2 answers:
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Using Lagrange multipliers, we have the Lagrangian
with partial derivatives (set equal to 0)
Substituting the first three equations into the fourth allows us to solve for
:
For each possible value of, we get two corresponding critical points at 
.
At these points, respectively, we get a maximum value of
and a minimum value of 
.
with partial derivatives (set equal to 0)
Substituting the first three equations into the fourth allows us to solve for
For each possible value of
At these points, respectively, we get a maximum value of
Answer:
Step-by-step explanation:
Let represent the number of monitors sold.
Given:
is the number of years since 1990.
So, for the year 1990, .
For the year 2000, 10 years passed. So, .
Now, monitors sold in 1990 are 150. So, at
Monitors sold in 2000 are 900. So, at
Thus, the two points are and
.
The slope of a line with points and
is given as:
Slope,
For the points and
, the slope is given as:
Slope,
Now, the y-intercept is the point where . So, the point
has
value as 0.
So, the y-intercept is 150.
Equation of a line in slope-intercept form is given as:
Where, is the slope and
is the y intercept.
Here, and
.
Therefore, the equation that represents the above data is given as:
