Question

Write an equation of the circle whose radius is 3 and whose center is (-1,6).

Answer 1

we are given

center=(-1,6)

radius=3

now, we can use standard equation of circle

$(x-h)^2+(y-k)^2=r^2$

where

center=(h,k)

radius =r

so, we get

center=(h,k)=(-1,6)

$h=-1,k=6$

radius =r=3

$r=3$

now, we can plug these values

and we get

$(x+1)^2+(y-6)^2=3^2$

$(x+1)^2+(y-6)^2=9$

so, option-D............Answer

Answer 2

D is correct . i just took the test