<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
</span>
<span>I hope this helps! </span>
Answer:
1.4000
2.5.551
3.6.8
4.10.00
5.4
Step-by-step explanation:
1 4066 as an example start from the end a 5 or more it turns to a zero and the one next to it
so in this case we now have 4100 but since it isn't 5 or more we make it a zero and move on so now we have 4000
sorry if I am wrong I am also an idiot so hopefully this helps for the future :)
Answer:
C. This was hard to do when I had this question
Answer: No
Step-by-step explanation: For x 0-2, the y is increasing by +5 every time. However, the moment it hits x=2, it starts decreasing by -5 every time. This means that it does not follow on set pattern (either +5 or -5) and looks more like a ^ than a /.
i think the answer is linear I am not sure though
