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rjkz [21]
3 years ago
14

Please help 6th grade math please please help i will give brainliest

Mathematics
1 answer:
inysia [295]3 years ago
4 0
Least value:16
Median:26
Greatest value:34
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Please help! I don't understand how to solve this problem
Ilia_Sergeevich [38]

Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

Assuming an uniform distribution, the standard deviation is given by:

S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The sample size is found solving for n when the margin of error is of M = 0.006, hence:

M = z\frac{\sigma}{\sqrt{n}}

0.006 = 1.96\frac{1.1547}{\sqrt{n}}

0.006\sqrt{n} = 1.96 \times 1.1547

\sqrt{n} = \frac{1.96 \times 1.1547}{0.006}

(\sqrt{n})^2 = \left(\frac{1.96 \times 1.1547}{0.006}\right)^2

n =  142,282.

A sample of 142,282 should be taken, which is not practical as it is too large of a sample.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0
1 year ago
What is 9.375 Rounded to the nearest hundredth
stiks02 [169]

Note the hundredth place value (underlined and bolded):

9.3<u>7</u>5

Look at the number to the right of the hundredth place value. It is a 5. Because you round up if the number is 5 or greater, you round up in this case (you round down if it is 4 or less).

9.375 rounded to the nearest hundredth is 9.38

~

3 0
3 years ago
Read 2 more answers
Simplify the expression. 4(11 + 7) ÷ (7 – 5) 40 36 47 5
vodomira [7]

Answer:

36

Step-by-step explanation:

6 0
2 years ago
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How to set up a linear equation from a chart
balandron [24]
Start anywhere basically, just keep the line to where it will always continue at a constant value. Dont curve the line for example, that would make it unlinear.
6 0
3 years ago
Use the given equation to find the missing coordinates of the points and then find the slope of the line for each equation. y=-3
skad [1K]

y=-\cfrac{3}{7}x+3 \\\\[-0.35em] ~\dotfill

A(x~~,~~\stackrel{y}{6})\qquad \qquad \begin{array}{llll} \stackrel{\textit{since we know that}}{y=-\cfrac{3}{7}x+3}\implies 6=-\cfrac{3}{7}x+3\implies 3=-\cfrac{3x}{7} \\\\\\ 21=-3x\implies \cfrac{21}{-3}=x\implies -7=x \end{array} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x}{9}~~,~~y)\qquad \qquad \begin{array}{llll} \stackrel{\textit{since we know that}}{y=-\cfrac{3}{7}x+3}\implies y=-\cfrac{3}{7}(9)+3\implies y=-\cfrac{27}{7}+3 \\\\\\ y=\cfrac{-27+21}{7}\implies y=-\cfrac{6}{7} \end{array}

5 0
2 years ago
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