<span>D. Like radical terms.</span>
We have to <u>evaluate</u> the given <u>expression</u>.
If we multiple both numerator and denominator by 1 - sin(x), then the value remains same. Let's do that.
![\rm = \sqrt{ \dfrac{[1 - \sin(x)][1 - \sin(x) ]}{[1 + \sin(x)][1 - \sin(x) ]} }](https://tex.z-dn.net/?f=%20%5Crm%20%3D%20%20%5Csqrt%7B%20%5Cdfrac%7B%5B1%20-%20%20%5Csin%28x%29%5D%5B1%20-%20%20%5Csin%28x%29%20%5D%7D%7B%5B1%20%2B%20%20%5Csin%28x%29%5D%5B1%20-%20%20%20%5Csin%28x%29%20%5D%7D%20%7D%20)
![\rm = \sqrt{ \dfrac{[1 - \sin(x)]^{2}}{1- \sin^{2} (x) } }](https://tex.z-dn.net/?f=%20%5Crm%20%3D%20%20%5Csqrt%7B%20%5Cdfrac%7B%5B1%20-%20%20%5Csin%28x%29%5D%5E%7B2%7D%7D%7B1-%20%20%20%5Csin%5E%7B2%7D%20%28x%29%20%7D%20%7D%20)
<u>We know that:</u>
Therefore, <u>the expression becomes:</u>
![\rm = \sqrt{ \dfrac{[1 - \sin(x)]^{2}}{\cos^{2} (x)}}](https://tex.z-dn.net/?f=%20%5Crm%20%3D%20%20%5Csqrt%7B%20%5Cdfrac%7B%5B1%20-%20%20%5Csin%28x%29%5D%5E%7B2%7D%7D%7B%5Ccos%5E%7B2%7D%20%28x%29%7D%7D%20)
Answer is x=2 bacause u just jave to listen. this is the equation . 3x+4=5x-2. solve
Answer:
4
Step-by-step explanation:
Slope is x2-y2/ x1-y1
So, its 6-10/1-2
or, -4/-1
Or 4.
Hope this helps you!
#Team Rainbows.
Answer: false
Step-by-step explanation:
If f and g are increasing on I, this implies that f' > 0 on I and g' > 0 on I. That is both f' and g' have a positive slope. However,
Using product rule;
(fg)' = fd(g) + gd(f)
(fg)' = f * g' + f' * g
and although it is given that g' and f' are both positive we don't have any information about the sign of the values of the functions themselves(f and g). Therefore, if at least one of the functions has negative values there is the possibility that the derivative of the product will be negative. For example;
f = x, g = 5x on I = (-5, -2)
f' = 1 and g' =5 both greater than 0
f and g are both lines with positive slopes therefore they are increasing, but f * g = 5x^2 is decreasing on I.
