4 years ago

If a sample of 5 keyboard is randomly selected what is the probability that at least 4

1 answer:

3 0

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Phantasy [73]

\left[A \right] = \left[ \frac{ - \left( 5 - 3\,x - 2\,x^{2} - 2\,x^{3}\right) }{-1-x}\right][A]=[−1−x−(5−3x−2x2−2x3)] I hope helping this answer

6 0

3 years ago

Vinvika [58]

Step-by-step explanation:

Since AE is the bisector of angle BAC,so angle BAE and Angle CAE is equal. Here Angle CAE and Angle EAC is same.

therefore,

m(Angle BAE)=m(Angle EAC)

$x + 30 = 3x - 10$

or, 2x=40

or, x=20

Hence,

m(Angle EAC)=

$3x - 10$

$(3 \times 20) - 10 = 60 - 10 = 50$

4 0

3 years ago

zloy xaker [14]

$(\frac{1}{4})^{-3}= (\frac{4}{1})^3\\\\=(4)^3\\\\=4\times 4\times 4\\\\=16\times 4\\\\=64$

Your final answer is B. 64.

8 0

3 years ago

Jet001 [13]

Answer: don't know sorry

Step-by-step explanation:

4 0

3 years ago

mezya [45]

Answer:

i don't think 3 works for x because the only solution for x was 8

Step-by-step explanation:

4 0

3 years ago