Ask question

Ask question

All categories

2 years ago

9

Sum of the exterior angles of polygons

1 answer:

Ne4ueva [31]2 years ago

6 0

Answer:

360° .

Step-by-step explanation:

You might be interested in

An isosceles triangle has an area of 32 cm2, and the angle between the two equal sides is 5π/6. Find the length of the two equal

taurus [48]

The area of a triangle can be determined by knowing 2 sides and their included angle of a certain triangle. Since both sides are equal, then they would just be denoted by a squared entity. This is done as follows:

A = x² sin∅
32 = x² sin (5*pi/6)

Make sure your calculator is in rad form.

32 = x² (1/2)
x = 8

Thus, each side is 8 cm.

7 0

2 years ago

A certain circle can be represented by the following equation. x^2+y^2+18x+14y+105=0 What is the center of the circle? What is t

Gre4nikov [31]

Answer:

See below.

Step-by-step explanation:

Recall the equation for a circle:

$(x-h)^2+(y-k)^2=r^2$ , where (h,k) is the center and r is the radius.

We need to turn the given equation into the above format. We do this by completing the square.

First, group them:

$(x^2+18x)+(y^2+14y)=-105$

For the first section, complete the square for $x^2+18x$ :

$x^2+18x+81-81$

$(x+9)^2-81$

Do the same for the second:

$y^2+14y$

$y^2+14y+49-49$

$(y+7)^2-49$

All together:

$((x+9)^2-81)+((y+7)^2-49)=-105$

$(x+9)^2+(y+7)^2-130=-105$

$(x+9)^2+(y+7)^2=25$

The center is (-9,-7).

The radius is $\sqrt{25}=5$

5 0

2 years ago

Someone please help me asap! :)

Kay [80]

Answer:

$a=5m$

Step-by-step explanation:

$m=\frac{a}{5}$

Swap sides:

$\frac{a}{5}=m$

Multiply both sides by 5:

$\frac{5a}{5}=5m$

$a=5m$

3 0

2 years ago

Read 2 more answers

Find the area between y=(x-2)ex and the x-axis from x=2 to x=4.

mojhsa [17]

Answer:

$e^4+e^2$

Step-by-step explanation:

It can be found by integral.

First let's find the intersection points.

$(x-2)e^x = 0$

Only intersection point is x = 2.

And it is asked to find the area in the interval (2, 4).

$\int\limits^4_2 (x-2)e^x \,dx=?$

We will use integration by parts.

$x-2=u\\dx=du\\e^xdx=dv\\e^x=v$

$\int\limits^4_2 (x-2)e^x \,dx=uv-\int vdu=(x-2)e^x-\int e^xdx=(x-2)e^x-e^x=\\\\=(x-3)e^x|^4_2=(4-3)e^4-(2-3)e^2=e^4+e^2$

3 0

3 years ago

Help please <br><br>numbers 12, 13, 14, 15<br><br>please show work

kari74 [83]

Those are the answers for 12,13,14,15

5 0

2 years ago