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solniwko [45]
2 years ago
9

Sum of the exterior angles of polygons

Mathematics
1 answer:
Ne4ueva [31]2 years ago
6 0

Answer:

360° .

Step-by-step explanation:

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The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 269 day
fenix001 [56]

Answer:

a) 279 b)254

Step-by-step explanation:

Mean = 269 days

standard deviation = 8 days

let n be the pregnancy lenght.  

using normal distribution formula

z = (n – mean)/ standard deviation

n = z * standard deviation + mean

Now, z values for the top 12% has to be found using a z table.

The top 12% means 88% of area under the curve. In this case z = 1,176

n = 1,176 * 8 + 269

n = 278.4 = 279

The bottom 3% means 97% of area under the curve. In this case z = -1,882

n = -1,882 * 8 + 269

n = 253.94 = 254

6 0
3 years ago
The marked price of an article is Rs 2,800 which is 40 % above the cost price. If it
mixer [17]

Answer:

mp=2800

mp=cp+40%ofcp=cp+40/100×cp=1.4cp

2800=1.4çp

cp=2800/1.4=2000

discount=20%

profit%=?

Step-by-step explanation:

sp=mp-discount%of mp=2800-20/100×2800=2240

profit=sp-cp=2240-2000=240

profit%=profit/cp×100%=240/2000×100%=12%

7 0
3 years ago
Trejon rides his bike 2 1/4 miles each day. Which equation can be used to find r, the number of miles he will ride in 8 days?​
LiRa [457]

Answer:

you got this sound from the human body for you so much I was wondering what to say I'm sorry I'm not going anywhere you want to go get me on snap now I got you can do this is the best of

8 0
3 years ago
Hey answer this pls!!​
Kitty [74]

Answer:

That would be A) -3/5.

Step-by-step explanation:

Here it is.

6 0
2 years ago
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
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