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3 years ago

If you roll a dice 100 times how many times would you expect to roll a product that is a multiple of 5

1 answer:

3 0

If you're rolling a single cube, then ...

-- There are 6 possible out comes.
-- One of them (5) is a multiple of 5 .
-- The probability of rolling it is (1/6) = 16-2/3 % .

If everything is acting perfectly random, then ion 100 rolls,
you'd expect to succeed 16 or 17 times.

If you're rolling a pair of cubes, then ...

-- There are (6 x 6) = 36 possible outcomes.
-- There are seven ways to get a multiple of 5.
(1+4), (4+1), (2+3), (3+2), (4+6), (6+4), (5+5)
-- The probability of rolling one of those is
(7/36) = 19-4/9 % .

If everything is acting perfectly random, then in 100 rolls,
you'd expect to succeed 19 or 20 times.

You might be interested in

How to solve 7m + 2n = 21 and 10m + 4n = -10 using substitution. Step by step please and thank you!

ryzh [129]

7m+2n=21
-7m -7m

2n=21-7m
2 2

n=21-7m
 2

10m+4(21-7m/2)= -10
-10m -10m

4(21-7m/2)= -10-10m

(84-28m/2)= -10-10m
x2 x2

84-28m = -20-20m
+20+28m +20+28m

104 = 8m
8 8

m=13

10(13) + 4n = -10
-130 -130

4n = -140
4 4

n= -35

If anything is unclear please feel free to ask.

5 0

3 years ago

Solve for x.

liraira [26]

First one
remember
a/b=c/d also can be written as
ad=bc

so
first one can be rewritten as
3x=96
divide both sides by 3
x=32

2nd ones we can just times both sides by 5 to get
x=50/12

3rd one we times 12 both sides to get
x=8

4th one we translate to
4x=63
divide by 4
x=63/4

5th one we translate to
99=5x
divide by 5
99/5=x

6th one we times 21 both sides
6=x

7th one we times both sides by 16
14=x

last one we translate to
45=3x
divide 3
15=x

5 0

3 years ago

How do I figurevout 2(x-y) and 2x-2y

Umnica [9.8K]

Answer:

2(x-y) and 2x-2y are equivalent.

Step-by-step explanation:

To figure out 2(x-y) and 2x-2y, you can apply the distributive property on

$2(x - y)$

to get:

$2(x - y) = 2x - 2y$

Or we can factor

$2x - 2y$

to get:

$2x - 2y = 2(x - y)$

This implies that, the two expressions are equivalent.

4 0

4 years ago

A rectangular box with a volume of 684 ftcubed is to be constructed with a square base and top. The cost per square foot for the

SCORPION-xisa [38]

Answer:

The dimensions of the rectangular box is 36.23 ft×36.23 ft×4.345 ft.

Minimum cost=2046.16 cents

Step-by-step explanation:

Given that a rectangular box with a volume of 684 ft³.

The base and the top of the rectangular box is square in shape

Let the length and width of the rectangular box be x.

[since the base is square in shape, length=width]

and the height of the rectangular box be h.

The volume of rectangular box is = Length ×width × height

=(x²h) ft³

$x^2h=684\Rightarrow h=\frac{684}{x^2}$ (1)

The area of the base and top of rectangular box is = x² ft²

The surface area of the sides= 2(length+width) height

=2(x+x)h

=4xh ft²

The total cost to construct the rectangular box is

=[(x²×20)+(x²×15)+(4xh×1.5)] cents

=(20x²+15x²+6xh) cents

=(25x²+6xh) cents

Total cost= C(x).

C(x) is in cents.

∴C(x)=25x²+6xh

Putting $h=\frac{684}{x^2}$

$C(x)=25x^2+6x\times\frac{684}{x^2} \Rightarrow C(x)=25x^2+\frac{4104}{x}$

Differentiating with respect to x

$C'(x)=50x-\frac{4104}{x^2}$

To find minimum cost, we set C'(x)=0

$\therefore50x-\frac{4104}{x^2}=0\\\Rightarrow50x=\frac{4104}{x^2}\\\Rightarrow x^3=\frac{4104}{50}\Rightarrow x\approx 4.345$ ft.

Putting the value x in equation (1) we get

$h=\frac{684}{(4.345)^2}$

≈36.23 ft.

The dimensions of the rectangular box is 36.23 ft×36.23 ft×4.345 ft.

Minimum cost C(x)=[25(4.345)²+10(4.345)(36.23)] cents

=2046.16 cents

5 0

3 years ago

Construct a 96% confidence interval if a sampling distribution has a mean of 20, a standard deviation of 5, and a size of 100.

MAXImum [283]

Using the t-distribution, the 96% confidence interval is given as follows:

(18.96, 21.04).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm t\frac{s}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

t is the critical value.

n is the sample size.

s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 96% confidence interval, with 100 - 1 = 99 df, is t = 2.0812.

The parameters are given as follows:

$\overline{x} = 20, s = 5, n = 100$

Hence the bounds of the interval are:

$\overline{x} - t\frac{s}{\sqrt{n}} = 20 - 2.0812\frac{5}{\sqrt{100}} = 18.96$

$\overline{x} + t\frac{s}{\sqrt{n}} = 20 + 2.0812\frac{5}{\sqrt{100}} = 21.04$

More can be learned about the t-distribution at brainly.com/question/16162795

#SPJ1

6 0

2 years ago