draw a rectangle around it:
the widest part is from about -3 to 2 which is 5 units wide
height is from 3 to -4, which is 7 units
5*7 = 35
the top and bottom are angled so you can subtract a little for that
so I would estimate around 32 square units
The perimeters of both are equal.
The side of the square is 12.
Therefore, its area equals to : 12² = 144
The rectangle base is 19.
Because it has the same perimeter as the square's, so rectangle perimeter is : 19 + 19 + side + side = 12 + 12 + 12 + 12
= 38 + 2side = 48
= 2side = 48 - 38
= side of rectangle = 5
Therefore, its area is 19 x 5 = 95
If you subtract it from the area of the square, you will get : 144 - 95 = 49.
So the answer is : the area of the square is 49 units largee than the area of the square (C)
If two similar triangles have sides in the ratio a : b, then their areas are in the ratio a² : b².
We have the ratio:

Area of the smaler triangle = x
Area of the larger triangle = 567 cm²
Therefore we have the equation:

<h3>Answer: C. 63 cm²</h3>
Answer:
The volume of the solid is the volume of the prism minus the volume of the cylinder.
For the cylinder, diameter = d = 4 cm
radius = d/2 = (4 cm)/2 = 2 cm
V = volume of prism - volume of cylinder
The volume of a prism is length times width times height.
The volume of a cylinder is pi times the square of the radius times the height.
V = LWH - (pi)r^2h
V = 6 cm * 6 cm * 15 cm - (pi)(2 cm)^2(15 cm)
V = 540 cm^3 - 60pi cm^3
V = (540 - 60pi) cm^3
The answer for your question is 6