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Olegator [25]
3 years ago
11

Find the surface area of a pyramid with a square base with dimensions 100 mm by 100 mm and height of 75 mm.

Mathematics
1 answer:
Reil [10]3 years ago
8 0

To solve for the surface area of the pyramid, we make use of the formula:

A= l w + l [sqrt ((w / 2)^2 + h^2)] + w [sqrt ((l / 2)^2 + h^2))

where,

l and w are the base of the pyramid = 100 mm

h is the height of the pyramid = 75 mm

 

Substituting the given values into the equation:

A= 100 * 100 + 100 [sqrt ((100 / 2)^2 + 75^2)] + 100 [sqrt ((100 / 2)^2 + 75^2))

A = 10,000 + 100 (sqrt 2575) + 100 (sqrt 2575)

A = 20,148.90 mm^2

 

Therefore the surface area of the pyramid is about 20,149 mm^2.

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A cashier has 30 bills, all of which are $10 or $20 bills. The total value of the money is $460. How many of each type of bill d
Andru [333]

Answer:

$10 bill = 14 and  $20 bill = 16.

Step-by-step explanation:

Given  : A cashier has 30 bills, all of which are $10 or $20 bills. The total value of the money is $460.

To find :  How many of each type of bill does the cashier have.

Solution : We have given that

A cashier has 30 bills

Let bill of $10  = x .

Bill of $20 = y .

Money of  $10  = 10x .

Money of  $20  = 20y.

Total bill

x + y = 30-------(1)

10x + 20y = 460-----(2)

On multiplying equation 1 by 10 and subtracting from equation 2.

10x + 20 y = 460

(-)10x +(-) 10 y =  (-)300

______________

0  +  10 y = 160 .

On dividing  by 10

y  = 16 .

Plug y = 16 in equation 1

x + 16  = 30

On subtracting both sides by 16.

x = 30 - 16.

x  = 14

Therefore, $10 bill = 14 and  $20 bill = 16.

4 0
4 years ago
Write 72 as a product of primes.<br> Use index notation where appropriate.
stiv31 [10]

Hi there!

~

The prime factorization for <u>72</u> is <u>2×2×2×3×3 </u>

Hope this helped you!

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3 years ago
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abruzzese [7]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The picture of the question in the attached figure

we know that

A translation and a reflection are rigid transformations, that produce congruent figures'

Remember that

Two figures are congruent if their corresponding sides and their corresponding angles are congruent

In this problem

Triangle JKL and Triangle J'K'L' are congruent

so

JL=J'L'

substitute the given values

8=2x-4

solve for x

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