Answer: The p(success) = 0.6
Your question is a little unclear, but I believe you are asking about the probability that at least one of the trials in the experiment were successful.
If that is the case, you simply have to add the probability of 1 success with the probability of 2 successes.
That is 0.48 + 0.16 = 0.64
Rounding our answer to one decimal place gives us 0.6.
Answer:-74
Step-by-step explanation: When you are in the megatives, less is more! So -74 is actually greater then -75
Answer:
Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.
<em>Reflexive: </em>We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that
. Thus, A↔A.
<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that
. In this equality we can perform a right multiplication by
and obtain
. Then, in the obtained equality we perform a left multiplication by P and get
. If we write
and
we have
. Thus, B↔A.
<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have
and from B↔C we have
. Now, if we substitute the last equality into the first one we get
.
Recall that if P and Q are invertible, then QP is invertible and
. So, if we denote R=QP we obtained that
. Hence, A↔C.
Therefore, the relation is an <em>equivalence relation</em>.
I’m pretty sure it looks like it’s D
Answer:
The probability that a product is defective is 0.2733.
Step-by-step explanation:
A product consists of 3 parts. If any one of the part is defective the whole product is considered as defective.
The probability of the 3 parts being defective are:
P (Part 1 is defective) = 0.05
P (part 2 is defective) = 0.10 P (part 3 is defective) = 0.15
Compute the probability that a product is defective as follows:
P (Defective product) = 1 - P (non-defective product)
= 1 - P (None of the 3 parts are defective)
= 1 - P (Part 1 not defective) × P (Part 2 not defective) × P (Part 1 not defective)
![=1-[(1-0.05)\times(1-0.10)\times (1-0.15)]\\=1-[0.95\times0.90\times0.85]\\=1-0.72675\\=0.27325\\\approx0.2733](https://tex.z-dn.net/?f=%3D1-%5B%281-0.05%29%5Ctimes%281-0.10%29%5Ctimes%20%281-0.15%29%5D%5C%5C%3D1-%5B0.95%5Ctimes0.90%5Ctimes0.85%5D%5C%5C%3D1-0.72675%5C%5C%3D0.27325%5C%5C%5Capprox0.2733)
Thus, the probability that a product is defective is 0.2733.