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Olegator [25]
3 years ago
11

Find the surface area of a pyramid with a square base with dimensions 100 mm by 100 mm and height of 75 mm.

Mathematics
1 answer:
Reil [10]3 years ago
8 0

To solve for the surface area of the pyramid, we make use of the formula:

A= l w + l [sqrt ((w / 2)^2 + h^2)] + w [sqrt ((l / 2)^2 + h^2))

where,

l and w are the base of the pyramid = 100 mm

h is the height of the pyramid = 75 mm

 

Substituting the given values into the equation:

A= 100 * 100 + 100 [sqrt ((100 / 2)^2 + 75^2)] + 100 [sqrt ((100 / 2)^2 + 75^2))

A = 10,000 + 100 (sqrt 2575) + 100 (sqrt 2575)

A = 20,148.90 mm^2

 

Therefore the surface area of the pyramid is about 20,149 mm^2.

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<em><u>Solution:</u></em>

Given that, area of rectangle is 4w - 10 square units

We have to factor the expression

From given,

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Thus the given expression is factored

<em><u>The area of rectangle is given as:</u></em>

Area\ of\ rectangle = length \times width

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From above we can say,

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Width = 2w - 5 or 2

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