Can someone explain this to me?
1 answer:
You might be interested in
Answer:
B)
Step-by-step explanation:
To find this recursive formula, we need to look at the relationship between each term in the sequence.
When looking at n=1 and n=2, we can see that we have 5 and 11.
We have to find a pattern between each term in the sequence. If we double 5, which is the previous term, and add 1, we get 11.
Lets see if this works for the next term, 23
First, lets double 11 = 22
Now add 22+1=23. We got the right term. Lets test it again
23*2=46
46+1=47
And now the last term
47*2=94
96+1=95
As you can see doubling the previous term and adding 1 works for all of these terms.
when written as a recursive formula, it would be , which is B
Hello, My Dear Friend!
Solution for
equation:
<span>Simplifying:
</span>
<span>
</span><span>Reorder the terms:
</span>
<span>
</span><span>Solving:
</span>
<span>
</span><span>Solving for variable 'x'.
</span>Move all terms containing x to the left, all other terms to the right.
<span>Add '12' to each side of the equation.
</span>
<span>
</span>Combine like terms:
<span>
</span><span>Combine like terms: </span>
<span>
</span><span>Divide each side by '20'.
</span>
<span>
</span><span>Simplifying:
</span><span>
Therefore, THAT is The Answer!^^^
</span>=====> x = 3 <=====
I Hope my answer has come to your Help. Thank you for posting your question here in
We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)
<span>
</span>
Solution for
<span>Simplifying:
</span>
</span><span>Reorder the terms:
</span>
</span><span>Solving:
</span>
</span><span>Solving for variable 'x'.
</span>Move all terms containing x to the left, all other terms to the right.
<span>Add '12' to each side of the equation.
</span>
</span>Combine like terms:
</span><span>Combine like terms: </span>
</span><span>Divide each side by '20'.
</span>
</span><span>Simplifying:
</span>
Therefore, THAT is The Answer!^^^
</span>=====> x = 3 <=====
I Hope my answer has come to your Help. Thank you for posting your question here in
<span>