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IgorC [24]
3 years ago
14

The midpoint of EF is M (4,10) one endpoint is E (2,6). Find the coordinates of the of the other endpoints F.

Mathematics
2 answers:
matrenka [14]3 years ago
4 0
Midpoint formula : (x1 + x2) / 2, (y1 + y2) / 2
(2,6)...x1 = 2 and y1 = 6
(x,y)...x2 = x and y2 = y
sub
(2 + x) / 2, (6 + y) / 2 = (4,10)

(2 + x) / 2 = 4
2 + x = 4 * 2
2 + x = 8
x = 8 - 2
x = 6

(6 + y)/2 = 10
6 + y = 10 * 2
6 + y = 20
y = 20 - 6
y = 14

so ur other endpoint is (6,14) <==
siniylev [52]3 years ago
4 0

Answer: Other point F ( 6 ,14).

Step-by-step explanation:

Given  : The midpoint of EF is M(4, 10). One endpoint is E(2, 6).

To find : Find the coordinates of the other endpoint F.

Solution : We have given  that

Line EF have mid point M ( 4 ,10)

One end point E ( 2 ,6) .

Let other point F ( )

Mid point segment formula ( M) : .

= 4

Plug  = 2.

= 4

On multiplying both side by 2

2 +   = 8

= 8- 2

 =  6.

= 10.

Plug  = 6.

= 10.

On multiplying both side by 2

6 +  = 20

= 20 - 6

= 14.

Therefore, Other point F ( 6 ,14).

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Brilliant_brown [7]

-2<em>x</em> + 6<em>y</em> = -38

3<em>x</em> - 4<em>y</em> = 32

To solve by elimination, multiply the top equation by 3 and the bottom equation by 2.

3(-2<em>x</em> + 6<em>y</em> = -38) --> -6<em>x</em> + 18<em>y</em> = -114

2(3<em>x</em> - 4<em>y</em> = 32) --> 6<em>x</em> - 8<em>y</em> = 64

Add the equations.

-6<em>x </em>+ 18<em>y</em> = -114

6<em>x</em> - 8<em>y</em> = 64

+_____________

0 + 10<em>y</em> = -50

10<em>y</em> = -50

<em>y</em> = -5

Substitute -5 for y into one of the original equations to find x.

3<em>x</em> - 4<em>y</em> = 32

3<em>x</em> - 4(-5) = 32

3<em>x</em> + 20 = 32

3<em>x</em> = 12

<em>x</em> = 4

Check work by plugging the <em>x</em>- and <em>y</em>-values into both of the original equations.

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-2(4) + 6(-5) = -38

-8 - 30 = 38

38 = 38


3<em>x</em> - 4<em>y</em> = 32

3(4) - 4(-5) = 32

12 + 20 = 32

32 = 32

Answer:

<em>x</em> = 4 and <em>y</em> = -5; (4, -5).

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Answer:

f(x)= 0, -1 ,5,14

g(x)= -6, -1, -1, 14

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B) g(x)=f(x)+k

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