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iVinArrow [24]
3 years ago
12

How can it be that 1^1 = 1 and 1^0 = 1, but 0^1 = 0? Can you explain it?

Mathematics
1 answer:
madam [21]3 years ago
8 0

Answer:

can u show the screen of the problem i dont understand ^

Step-by-step explanation:

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PLEASE HELP THANKS <3
igor_vitrenko [27]

Answer:

DL

Step-by-step explanation:

6 0
2 years ago
Whisper the numbers in standard form ( 1 hundred 3 tens 4 ones
Colt1911 [192]
Umm i answer is looking 134
8 0
3 years ago
Read 2 more answers
2,10,18,26 find the 61st term
saw5 [17]

Answer:

482

Step-by-step explanation:

We can see that the numbers shown resemble an arithmetic sequence because they have a common difference. The formula for the nth term of an arithmetic sequence is:

a_{n} =a_{1} +(n-1)d

Where a_{1} is the first term, a_{n} is the nth term, and d is the common difference. To find the 61st term, all we need is the first term and the common difference. By looking at what given, we can say the first term is 2. Now, to find the common difference, we find the difference of a term from the term before it. In this case we can do 10-2, which is 8 , or the common difference. Since we have everything we need, it can be plugged into the equation:

a_{61} =2 + (61 - 1)*8\\a_{61} = 2 + 60*8\\a_{61} = 2 + 480\\a_{61} = 482

So, the 61st term is 482.

4 0
2 years ago
Billie solved the equation below by completing the square, but she got the incorrect solution. In which step did Billie first ma
Tanzania [10]

Answer:

step 2

Step-by-step explanation:

we have

x^{2} +10x-49=0 ---> given problem

step 1

Move the constant to the right side

x^{2} +10x=49

the step 1 is correct

step 2

Complete the square

x^{2} +10x+5^2=49+5^2

x^{2} +10x+5^2=74

<u><em>The step 2 is not correct</em></u>

step 3

Rewrite as perfect squares

(x+5)^{2}=74

step 4

take square root both sides

x+5=\pm\sqrt{74}

step 5

Find the values of x

x=-5\pm\sqrt{74}

x=-5+\sqrt{74}

x=-5-\sqrt{74}

5 0
3 years ago
PLS help i rly need help ive posted with no help im rly confused
vesna_86 [32]
Asked and answered elsewhere.
brainly.com/question/8666894
8 0
3 years ago
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