Answer:
1a: f(x) = x³ -6x² +9x -4
1b: no breaks; the function is defined everywhere
2a: (-∞, 5]
2b: y = -3; y = -1
2c: x → -∞, y → -3; x → ∞, y → -1
Step-by-step explanation:
<h3>1A:</h3>
The factored form of f(x) is ...
f(x) = (x -4)(x -1)²
f(x) = (x -4)(x² -2x +1) = x³ -2x² +x -4x² +8x -4
f(x) = x³ -6x² +9x -4
__
<h3>1B:</h3>
The function h(x) is defined for all values of x to be either f(x) or g(x). The function f(x) is a polynomial function, so has no breaks in its domain. The function g(x) is defined for all values of x, so has no breaks in its domain.
There are no breaks in the domain of h(x).
__
<h3>2A:</h3>
See the attachment for a graph.
-∞ < y ≤ 5 . . . . range of f(x)
__
<h3>2B:</h3>
The asymptote as x → -∞ is the asymptote of the exponential function. The exponential term has an asymptote of y=0, but shifting it down 3 units means the asymptote is 0 -3:
x → -∞, y → -3 . . . . asymptote is y = -3
The asymptote as x → ∞ is the asymptote of the rational expression. That is the ratio of the leading terms: -x²/x² = -1.
x → ∞, y → -1 . . . . asymptote is y = -1
__
<h3>2C:</h3>
See part B.
7 lies betwee the 2 square integers 16 and 25.
Answer:
f(x) = ![-2^{x+1}-1](https://tex.z-dn.net/?f=-2%5E%7Bx%2B1%7D-1)
Step-by-step explanation:
I. If you see (0, -3) point on the green line
II. Perform x = 0, if y = -3 means the statement is true
= ![-2^{0+1} - 1](https://tex.z-dn.net/?f=-2%5E%7B0%2B1%7D%20-%201)
=
- 1
= -2 - 1
y = -3
Got more question or somethin to discuss? Leave comment below
Answer with explanation:
We have to graph the Linear equation:
→ y-4 =x+2
⇒To draw a line you need two points that lies on the line.
→Point (-2,4) lies on the line,as
L HS→4-4=0
R HS → -2 +2=0
→From Point (-2,4) finding a point which is left 1 unit and down 3 units is equal to = (-2-1 ,4-3)
= (-3,1)
→And from Point (-2,4) finding a point which is left 3 unit and down 1 unit is equal to = (-2-3 ,4-1)
= (-5,3)
→None of the two points that is (-3,1) and (-5,3) lie on the linear function
which is, y-4 =x+2.
≡None of the option
Answer:
he got some diabetes but the answer is looking it up o-o
Step-by-step explanation: