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gayaneshka [121]
3 years ago
7

F(x) = 3x + 2 and g(x) = x + 5

Mathematics
1 answer:
hjlf3 years ago
5 0

Answer:

G(f(x)) = A. 3x + 7

Step-by-step explanation:

Plug F(x) into the x on G. so (3x+2) +5 = 3x+7

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For what values of x is x^2 +2x=24 true
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Answer: x=4, x=-6

Step-by-step explanation:

set the equation equal to 0. solve for the x using the x method.

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What are the coefficients in the expression 4x - 2y + 1
Vikentia [17]

Answer:

The leading coefficient is 4

Step-by-step explanation:

8 0
4 years ago
Wayne Gretsky scored a Poisson mean six number of points per game. sixty percent of these were goals and forty percent were assi
BartSMP [9]

Answer:

a) The mean for the total revenue he earns per game is of 13.2K while the standard deviation is of 3.63K.

b) 0.05 = 5% probability that he has four goals and two assists in one game

Step-by-step explanation:

In hockey, a point is counted for each goal or assist of the player.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval. The standard deviation is the square root of the mean.

(a) Find the mean and standard deviation for the total revenue he earns per game.

60% of six are goals, which means that 60% of the time he earned 3K.

40% of six are goals, which means that 40% of the time he earned 1K.

The mean is:

\mu = 6*0.6*3 + 6*0.4*1 = 13.2

The standard deviation is:

\sigma = \sqrt{\mu} = \sqrt{13.2} = 3.63

The mean for the total revenue he earns per game is of 13.2K while the standard deviation is of 3.63K.

(b) What is the probability that he has four goals and two assists in one game

Goals and assists are independent of each other, which means that we find the probability P(A) of scoring four goals, the probability P(B) of getting two assists, and multiply them.

Probability of four goals:

60% of 6 are goals, which means that:

\mu = 6*0.6 = 3.6

The probability of scoring four goals is:

P(A) = P(X = 4) = \frac{e^{-3.6}*(3.6)^{4}}{(4)!} = 0.19122

Probability of two assists:

40% of 2 are assists, which means that:

\mu = 6*0.4 = 2.4

The probability of getting two assists is:

P(B) = P(X = 2) = \frac{e^{-2.4}*(2.4)^{2}}{(2)!} = 0.26127

Probability of four goals and two assists:

P(A \cap B) = P(A)*P(B) = 0.19122*0.26127 = 0.05

0.05 = 5% probability that he has four goals and two assists in one game

5 0
3 years ago
Explain the answer (Please help.) Asp
SSSSS [86.1K]

Hello from MrBillDoesMath!

Answer:

(1/x) * ( (1/ln7) -  (1/ln9) )

Discussion:

Using the change of base formula

log_b(x) = ln(x) / ln(b) sp       where _b means to log to base b

f(x) = ln(x)/ln(7) - ln(x)/ln(9)

so

f' = (1/x) *(1/ln7) - (1/x) *(1/ln9)

  = (1/x) * ( (1/ln7) -  (1/ln9) )

Thank you,

MrB

3 0
3 years ago
The volume of a cube is 512 cm3.
dalvyx [7]
The answer is D, the number of cubic units would decrease.

3 0
3 years ago
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