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maks197457 [2]
3 years ago
5

The four corners of a square are located at (-7, -2), (-7,5), (0,5), and (0, -2). What is the perimeter of the square?

Mathematics
1 answer:
12345 [234]3 years ago
8 0

Answer:

A)14 Units is the answer for this question

but check it

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A restaurant manager collected data on the number of customers in a party in the restaurant and the time elapsed until the party
Stella [2.4K]

Answer:

Option C The parties with a larger number of customers are associated with the longer times elapsed until the party left the restaurant.

Step-by-step explanation:

The correlation coefficient 0.78 shows that positive association between two variables number of customers and elapsed time until party left restaurant.

The positive association means that as the number of customers in a party increases the elapsed time also increase. So, we can say that the parties with a larger number of customers are associated with the longer times elapsed until the party left the restaurant.

4 0
3 years ago
Find the center, vertices, and foci of the ellipse with equation 2x2 + 8y2 = 16.
Pavlova-9 [17]

{2}x^{2}  + 8 {y}^{2}  = 16 \\  \\ 1. \:  {2x}^{2}  =  - 8 {y}^{2}  + 16 \\ 2. \:  {x}^{2}  =  - 4y^{2}  + 8 \\ 3. \: x =  \sqrt{ - 4y^{2}  + 8}  \\ x =  -  \sqrt{ - 4y^{2} + 8 }  \\  \\ answer \\ x =  \sqrt{ - 4y^{2} + 8 }  \\ x =  -  \sqrt{ - 4y^{2}  + 8}

4 0
3 years ago
The ratio of men to women working for a company is to 8 to 5 . If there are employees total 208 , how many women work for the co
Vikki [24]

Answer:

130

ratio of woman to man is : 5/8

5/8×208=130

8 0
2 years ago
Read 2 more answers
Navy PilotsThe US Navy requires that fighter pilots have heights between 62 inches and78 inches.(a) Find the percentage of women
Zigmanuir [339]

The first part of the question is missing and it says;

Use these parameters: Men's heights are normally distributed with mean 68.6 in. and standard deviation 2.8 in. Women's heights are normally distributed with mean 63.7 in. and standard deviation 2.9 in.

Answer:

A) Percentage of women meeting the height requirement = 72.24%

B) Percentage of men meeting the height requirement = 0.875%

C) Corresponding women's height =67.42 inches while corresponding men's height = 72.19 inches

Step-by-step explanation:

From the question,

For men;

Mean μ = 68.6 in

Standard deviation σ = 2.8 in

For women;

Mean μ = 63.7 in

Standard deviation σ = 2.9 in

Now let's calculate the standardized scores;

The formula is z = (x - μ)/σ

A) For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.7224

So, percentage of women meeting the height requirement is 72.24%.

B) For men;

Z = (62 - 68.6)/2.8 = -2.36

Z = (78 - 68.6)/2.8 = 3.36

Thus, the probability of only men will take the form of;

P(-2.36 < Z < 3.36) = P(Z<3.36) - P(Z > - 2.36)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<3.36) = 0.99961

And P(Z > -2.36) = 0.99086

Thus;

P(Z<3.36) - P(Z > -2.36) 0.99961 - 0.99086 = 0.00875

So, percentage of women meeting the height requirement is 72.24%.

B)For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.00875

So, percentage of women meeting the height requirement is 0.875%

C) Since the height requirements are changed to exclude the tallest 10% of men and the shortest10% of women.

For women;

Let's find the z-value with a right-tail of 10%. From the second table i attached ;

invNorm(0.90) = 1.2816

Thus, the corresponding women's height:: x = (1.2816 x 2.9) + 63.7= 67.42 inches

For men;

We have seen that,

invNorm(0.90) = 1.2816

Thus ;

Thus, the corresponding men's height:: x = (1.2816 x 2.8) + 68.6 = 72.19 inches

7 0
3 years ago
Find the surface area of a cylinder with a height of 8 yd and a base radius of 3 yd. Use 3.14 for π and dont do any rounding.
gulaghasi [49]
<span>Surface area</span> = 2πr(h+r) =  2 * 3.14 * 3(8+3) = 207.24 yd²
3 0
3 years ago
Read 2 more answers
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