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Hitman42 [59]
3 years ago
5

Which statement is true for the equation 5n − 4 = 5n − 3?

Mathematics
1 answer:
Molodets [167]3 years ago
8 0

Answer:

no solution

Step-by-step explanation:

  1. add 4 to each side
  2. subtract 5n to both sides
  3. answer 0=1
  4. no solution

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Mr. Lester's maximum heart rate is 180 beats per minute. When he exercises at the gym.
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Answer: 108

Step-by-step explanation: 60% of 180 is 108

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Ok is it 15/28 or 75/135  thatx is evuviulent to 25/45
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You also need to brake down this answer farther.
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The mayor of a town has proposed a plan for the annexation of an adjoining community. A political study took a sample of 1600 vo
Arturiano [62]

Answer:

Test statistic = -2.44

There is enough evidence to support the strategist's claim.

Step-by-step explanation:

H0 : p = 0.41

H1 : p < 0.41

pˆ = 0.38

Test statistic :

z=pˆ−p/√p(1−p)/n

Z = (0.38 - 0.41) / √(0.41(1 - 0.41) / 1600

Z = - 0.03 / √0.0001511875

Z = - 0.03 / 0.0122958

Z = - 2.4399

Test statistic = -2.44

The Pvalue :

P(Z < -2.44) = 0.0073436

α - level = 0.02

If Pvalue < α ; Reject H0

0.0073436 < 0.02 ; We reject H0

Since Pvalue < α ; Hence, There is enough evidence to support the strategist's claim.

8 0
2 years ago
A manufacturer has been selling 1000 flat-screen TVs a week at $500 each. A market survey indicates that for A manufacturer has
luda_lava [24]

Answer:

a) Demand function: q=6000-10\cdot p

b) The rebate should be of $200, so the sale price becomes $300 per unit.

c) The rebate should be of $150, so the sale price becomes $350 per unit.

Step-by-step explanation:

a) In this case, we have a known point of the demand function (1000 units sold at $500), and the slope of a linear function (increase by 100 units fora decrease in $10).

We can express the demand function (linear) as:

q=b+m\cdot p

To calculate the slope m, we use:

m=\Delta q/\Delta p=(+100)/(-10)=-10

To calculate b, we use the known point and the calculated slope:

q=b+m\cdot p\\\\b=q-m\cdot p=1000-(-10)\cdot (500)=1000+5000=6000

Then the demand function is:

q=6000-10\cdot p

b) The revenue can be expressed as:

R=q\cdot p = (6000-10p)\cdot p=6000p-10p^2

To maximize, we can derive and equal to zero

dR/dp=6000-2*10p=0\\\\20p=6000\\\\p=300

The rebate should be of $200, so the sale price becomes $300 per unit.

c) If we take into account the cost, we have that

R=q\cdot p-C=(6000p-10p^2)-(68000+100q)\\\\R=(6000p-10p^2)-(68000+100(6000-10p))\\\\R=6000p-10p^2-(68000+600000-1000p)\\\\R=-10p^2+7000p-668000

To maximize, we can derive and equal to zero

dR/dp=-20p+7000=0\\\\p=7000/20=350

The rebate should be of $150, so the sale price becomes $350 per unit.

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3 years ago
How many Tables are needed to make a long table that will seat 22 people
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How long are the tables
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