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k0ka [10]
3 years ago
12

One side of triangle is half the longest side. The third side is

Mathematics
1 answer:
Keith_Richards [23]3 years ago
6 0
Let S be the first side. 
Longest side is then 2S.
Third side is 2S-10.
Perimeter is sum of all three sides = S+2S+2S-10 = 75
=>
5S-10=75
5S=75+10=85
S=17

Therefore
S=17 is the first side. 
Longest side is then 2S=2*17=34.
Third side is 2S-10=2*17-10=24.
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[2x(3+5)+6]x4 what is the value of this expression
Gekata [30.6K]

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16x5+6x4

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Max makes and sells posters. The function p(x)= -10x^2 +200x -250, graphed below, indicates how much profit he makes in a month
viktelen [127]
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
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0 = 200 - 20x
20x = 200
x = 10                         
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750

Correct answer is C)
</span>
7 0
3 years ago
On rainy days, Izzy goes from his house to the school by running 1.2 miles on West St, then makes a 90º turn and runs 0.5 miles
OlgaM077 [116]

Answer:

a) It will take Izzy 0.226 hours = 13.6 minutes = 13 minutes 36 seconds to run to school on dashed days.

b) Izzy runs 1.30 miles on dry days.

c) Izzy saves 3 minutes and 12 seconds cutting through the woods.

Step-by-step explanation:

This problem can be solved by a simpe rule of three problem.

a) On rainy days, she runs 1.2 + 0.5 = 1.7 miles.

The problem states that for rainy days, she runs 7.5 miles per hour. We know that in a hour, Izzy will run 7.5 miles. We want to know how long it takes for her to run 1.7 miles. So

1 hour - 7.5 miles

x hours - 1.7 miles

7.5x = 1.7

x = \frac{1.7}{7.5}

x = 0.226 hours

It will take Izzy 0.226 hours = 13.6 minutes = 13 minutes 36 seconds to run to school on dashed days.

b) Now we have a right triangle, where the sides are the 1.2 miles and the 0.5miles, and the path through the woods x is the hypotenuse.

So, we apply the pythagorean theorem.

x^{2} = (1.2)^{2} + (0.5)^{2}

x^{2} = 1.44 + 0.25

x^{2} = 1.69

x = 1.30

So, Izzy runs 1.30 miles on dry days.

c) The first step for this question is knowing how long it takes for Izzy to run 1.30 miles at 7.50 miles a hour. So:

1 hour - 7.50 miles

x hours = 1.30 miles

7.50x = 1.30

x = \frac{1.3}{7.5}

x = 0.173 hours

So, it takes Izzy 0.173 hours = 10.4 minutes = 10 minutes 24 seconds to run through the woods.

13' 36''

-10' 24''

3' 12''

Izzy saves 3 minutes and 12 seconds cutting through the woods.

5 0
3 years ago
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