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3 years ago

What is 6 thousandths of a meter of a decimal

Mathematics

2 answers:

kari74 [83]3 years ago

6 0

0.006 , that is the answer.

Svetllana [295]3 years ago

5 0

0.006
That's you're answer

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While driving your rental car on your vacation in Europe, you find that you are getting 12.7 km/L of gasoline. What does this va

4vir4ik [10]

Steps: for an approximate result, multiply the fuel economy value by 2.352
12.7*2.352=29.87

Answer: 29.87 Miles per Gallon

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2 years ago

Each square represents one square foot. Estimate the area of the figure below.

Leona [35]

Uhm I’m gonna go with 14?

7 0

2 years ago

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Sophie has two new fish. She feeds one fish

Zielflug [23.3K]

Step-by-step explanation:

One fish eats = 4 pellets

Second fish eats = 5 pellets

No of days one fish stays with Sophie = 72 ÷ 4 = 18 days

No of days second fish stays with Sophie = 72 ÷ 5 = 14.4 days

4 0

3 years ago

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A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions

faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3>Solution:</h3>

Given that

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

The area of rectangle is given as:

$\text {Area of rectangle }=length \times width$

Area of rectangular parking lot = length of rectangular parking plot $\times$ width of the rectangular parking

$\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}$

But it is given that Area of rectangular parking lot = 15000 square feet

$\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}$

Solving the above quadratic equation using quadratic formula

General form of quadratic equation is

${ax^{2}+\mathrm{b} x+\mathrm{c}=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}$

$\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}$

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0

3 years ago

Help me please I will give brainlest!

Makovka662 [10]

2(x+7)3X

I think... look it up though to be sure

8 0

3 years ago

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