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Aloiza [94]
2 years ago
14

Some people advise that in very cold​ weather, you should keep the gas tank in your car more than half full. ​Irene's car had 5.

5 gallons in the ​14-gallon tank on the coldest day of the year. filled the tank with gas that cost ​$3.50 per gallon. How much did Irene spend on​ gas?
Mathematics
2 answers:
Tems11 [23]2 years ago
5 0
14-5.5= 8.5 gal she needs to fill
$3.5x8.5= $29.75

Answer:
Irene spends $29.75 on gas.
NARA [144]2 years ago
4 0
49 dollars 3.50x14 hope this helps
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A scientist in the lab is measuring a beetle to be 32 millimeters long, how much is that in meters?
RUDIKE [14]
32 millimeters = 0.032 meters
5 0
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What is the x please answer me quick ​
nordsb [41]
First u do a squared +b squared =c squared aka pythagorean theorem then so u already have c squared so you would do 5x5=25 and 13x13=169 so then the equation would be 25+?=169 then do 169-25 which equals 144 and then do the square root of that which is 12 THE ANSWER IS 12
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Joe wanted to buy some shoes. He found a pair at Paymore that cost $35. He had a coupon for 15%, what was the amount that Joe sp
lozanna [386]

Answer:

$29.75(without tax)    (I don't know if you need it with tax)

Step-by-step explanation:

3 0
2 years ago
Please select the best answer and click submit Solve kx-4=9 for x
shepuryov [24]

Answer:

Option B. x = \frac{13}{k}.

Step-by-step explanation:

The given equation is kx - 4 = 9

We will add 4 on both the sides of the equation

kx - 4 +4 = 9 +4

kx = 13

Now we will divide by k on both the sides of the equation

\frac{1}{k}(13x) = \frac{1}{k}13

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Therefore Option B x = 13/k is the right answer.

6 0
3 years ago
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Evaluate the following limit:
Makovka662 [10]

If we evaluate the function at infinity, we can immediately see that:

        \large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle L = \lim_{x \to \infty}{\frac{(x^2 + 1)^2 - 3x^2 + 3}{x^3 - 5}} = \frac{\infty}{\infty}} \end{gathered}$}

Therefore, we must perform an algebraic manipulation in order to get rid of the indeterminacy.

We can solve this limit in two ways.

<h3>Way 1:</h3>

By comparison of infinities:

We first expand the binomial squared, so we get

                         \large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}

Note that in the numerator we get x⁴ while in the denominator we get x³ as the highest degree terms. Therefore, the degree of the numerator is greater and the limit will be \infty. Recall that when the degree of the numerator is greater, then the limit is \infty if the terms of greater degree have the same sign.

<h3>Way 2</h3>

Dividing numerator and denominator by the term of highest degree:

                            \large\displaystyle\text{$\begin{gathered}\sf L  = \lim_{x \to \infty}\frac{x^{4}-x^{2} +4  }{x^{3}-5  }  \end{gathered}$}\\

                                \ \  = \lim_{x \to \infty\frac{\frac{x^{4}  }{x^{4} }-\frac{x^{2} }{x^{4}}+\frac{4}{x^{4} }    }{\frac{x^{3} }{x^{4}}-\frac{5}{x^{4}}   }  }

                                \large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} }  }{\frac{1}{x}-\frac{5}{x^{4} }  }  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

5 0
2 years ago
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