Let x be the length of the train.
On the basis of the observer;
Speed of the train = x/6
On the basis of the bridge;
Total distance covered by any point of the train= 350+x
Speed = (350+x)/20
Equating the two expressions of speed;
x/6 = (350+x)/20
20(x) = 6(350+x)
20x = 2100+6x
(20-6)x = 2100
14x = 2100
x= 2100/14 = 150 m
Speed = x/6 = (350+x)/20 = 150/6 = 500/20 = 25 m/s.
Therefore,
Length of train = 150 m
Speed of train = 25 m/s
Answer:
5
or
square root of 25
Step-by-step explanation:
I used my ti-84 plus ce calculator to solve
>download DISTMID
>prgm
>DISTMID
>DISTENCE
>enter points
>answer
80 Because the numbers are going up by 10
So you do 93 times 60 because it said you have to do 6 ten times and that equal 5580
