We have that
<span>y=1/2x-3
1) the slope of this line equation is m=(1/2)
2) the coordinates of the y intercept are
for x=0
y=-3
point (0,-3)
3)</span>the coordinates of the x intercept are
for y=0
0=(1/2)x-3------> (1/2)x=3----> x=6
point (6,0)
<span>if the line is dilated by a factor of 3
then
</span>y=1/2x-3--------> 3y=3*[1/2x-3]-----> 3y=(3/2)x-9
3y=(3x-18)/2-------> y=(3x-18)/6--------> y=(3/6)x-18/6
y=(3/6)x-18/6
so
1) the slope of this line equation is m=(3/6)-----> 3/6=1/2
2) the coordinates of the y intercept are
for x=0
y=-18/6-------> y=-3
point (0,-3)
3)the coordinates of the x intercept are
for y=0
0=(3/6)x-18/6------> (3/6)x=18/6----> x=18/3------> x=6
point (6,0)
therefore
the equation of the line
y=1/2x-3 is the same that the equation of the line y=(3/6)x-18/6
<span>the equation does not change because the slope and the x and y intercepts do not change either</span>
Answer:
the answer is 10832
Step-by-step explanation:
you can use a calculator
Answer:
The answer is "x-h and y-k".
Step-by-step explanation:
The center is (h, k) with E (x, y) point, and its length of the legs used during extracting the standard circle equation should be found. Its right triangle length base is (x-h) units, as well as the right triangle's length, is (y-k). So, these are the required leg lengths, that's why the above-given points are correct.
Answer:
A. Right 6, Down 5
Step-by-step explanation:
I don't know how to explain this
Answer:
Step-by-step explanation:
both slopes multiply each others must equal to -1 for perpendicular.
Let m1 = 3/2
Therefore -2/3 is perpendicular to 3/2. Because the line passes through (6,-2)
Given (x1, y1) = ordered pair
Therefore (x1, y1) = (6,-2)
and m = - 2/3
Write in slope-intercept form.
