The area and perimeter of the picture is 576 inches square and 96 inches respectively
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How to determine the area</h3>
Given that each frame is a rectangle and four frames makes up the picture
Note that the picture takes the shape of a square
Let's find the total perimeter
Perimeter of the picture = sum of the four rectangular frame perimeters
Perimeter = 24 + 24 + 24 + 24
Perimeter = 96 inches
Formula for area of a square = a^2
Where 'a' is the length of the side = 24 inches
Substitute the value of 'a'
Area of the picture = 24^2
Area of the picture = 576 inches square
Thus, the area and perimeter of the picture is 576 inches square and 96 inches respectively.
Learn more about a square here:
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If
(2 sin(x) - 1) (2 cos²(x) - 1) = 0
then either
2 sin(x) - 1 = 0 or 2 cos²(x) - 1 = 0
sin(x) = 1/2 or cos(2x) = 0
The first equation gives two families of solutions,
x = arcsin(1/2) + 2nπ = π/6 + 2nπ
x = π - arcsin(1/2) + 2nπ = 5π/6 + 2nπ
where n is any integer; we get the solutions x = π/6 and x = 5π/6 in the interval 0 ≤ x < 2π when n = 0.
The second equation also gives two families of solutions,
2x = arccos(0) + 2nπ = π/2 + 2nπ
2x = -arccos(0) + 2nπ = -π/2 + 2nπ
Divide both sides by 2 :
x = π/4 + nπ
x = -π/4 + nπ
Then the solutions we want are x = π/4 and x = 5π/4 (when n = 0 and 1 in the first family, respectively) and x = 3π/4 and x = 7π/4 (when n = 1 and 2 in the second family).
We have 6 solutions, so A is the correct choice.
Answer:
48 points thxs
Step-by-step explanation:
