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3 years ago

I need help RN. its due today before midnight.

Mathematics

1 answer:

Anika [276]3 years ago

7 0

Im sorry I cant help im in 6th grade

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The left side of a solid block is held at a constant temperature of 200°C. The temperature profile within the block is given by

Nikitich [7]

Answer:

with T = 50⁰C, we have:

50 = 200 - 5x - x²

<=> x² + 5x = 150

<=> x² + 5x - 150 = 0

=> x = 10

6 0

3 years ago

8. What’s the answer to this question?

marta [7]

Answer:

Step-by-step explanation:

nani

5 0

3 years ago

A movie theater has been charging $10.00 per person and selling about 500 tickets on a typical weeknight. After surveying their

kifflom [539]

Answer:

$p(x) = -0.01x + 15$

Step-by-step explanation:

Given

Let x represent the number of tickets, and p the charges

$(x_1,p_1) = (500,10)$

A reduction of 50c gives an increment of 50 tickets.

This gives:

$(x_2,p_2) = (500+50,10-0,5)$ ---- $50c = \$0.5$

$(x_2,p_2) = (550,9.5)$

Required

Determine the demand function

First, calculate the slope:

$m = \frac{p_2 - p_1}{x_2 - x_1}$

$m = \frac{9.5 - 10}{550-500}$

$m = \frac{-0.5}{50}$

$m = -0.01$

So, the equation is:

$p = m(x - x_1) + y_1$

$p = -0.01(x - 500) +10$

$p = -0.01x + 5 +10$

$p = -0.01x + 15$

Hence, the function is:

$p(x) = -0.01x + 15$

4 0

3 years ago

Find equivalent ways to rewrite the expression 6a^8÷3a^4

solong [7]

Answer:

6a^8/3a^4= (6/3)= 2

a^8/a^4= a^4

2a^4

(6/3)(a^8/a^4)= 2a^4

(6/3)(a^(8-4))= 2a^4

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

In ΔABC, m∠B = m∠C. The angle bisector of ∠B meets AC at point H and the angle bisector of ∠C meets AB at point K. Prove that BH

solniwko [45]

Answer:

See explanation

Step-by-step explanation:

In ΔABC, m∠B = m∠C.

BH is angle B bisector, then by definition of angle bisector

∠CBH ≅ ∠HBK

m∠CBH = m∠HBK = 1/2m∠B

CK is angle C bisector, then by definition of angle bisector

∠BCK ≅ ∠KCH

m∠BCK = m∠KCH = 1/2m∠C

Since m∠B = m∠C, then

m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)

Consider triangles CBH and BCK. In these triangles,

∠CBH ≅ ∠BCK (from equality (*));
∠HCB ≅ ∠KBC, because m∠B = m∠C;
BC ≅CB by reflexive property.

So, triangles CBH and BCK are congruent by ASA postulate.

Congruent triangles have congruent corresponding sides, hence

BH ≅ CK.

5 0

3 years ago