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4 years ago

6

Using this nomogram, what is the magnitude of an earthquake that is 500 km from a seismic station and has an amplitude of 0.2 mm

?

1 answer:

Novay_Z [31]4 years ago

6 0

<span>From the given nomogram, the magnitude of an earthquake that is 500 km from a seismic station and has an amplitude of 0.2 mm is 4</span>

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Find the area between y=(x-2)ex and the x-axis from x=2 to x=4.

mojhsa [17]

Answer:

$e^4+e^2$

Step-by-step explanation:

It can be found by integral.

First let's find the intersection points.

$(x-2)e^x = 0$

Only intersection point is x = 2.

And it is asked to find the area in the interval (2, 4).

$\int\limits^4_2 (x-2)e^x \,dx=?$

We will use integration by parts.

$x-2=u\\dx=du\\e^xdx=dv\\e^x=v$

$\int\limits^4_2 (x-2)e^x \,dx=uv-\int vdu=(x-2)e^x-\int e^xdx=(x-2)e^x-e^x=\\\\=(x-3)e^x|^4_2=(4-3)e^4-(2-3)e^2=e^4+e^2$

3 0

3 years ago

2/3 + 1/4 what is a simplified expression?

Anna35 [415]

Answer:

11/12

Step-by-step explanation:

We need to get a common denominator of 12

2/3 *4/4 = 8/12

1/4 *3/3 = 3/12

2/3 +1/4

8/12+3/12

11/12

5 0

3 years ago

3 regions are defined in the figure find the volume generated by rotating the given region about the specific line

anastassius [24]

The volume generated by rotating the given region $R_{3}$ about OC is $\frac{4}{g} \pi$

<h3>Washer method</h3>

Because the given region ( $R_{3}$ ) has a look like a washer, we will apply the washer method to find the volume generated by rotating the given region about the specific line.

solution

We first find the value of x and y

$y=2(x)^{\frac{1}{4} }$

$x=(\frac{y}{2} )^{4}$

$y=2x$

$x=\frac{y}{2}$

$\int\limits^a_b {\pi } \, (R_{o^{2} } - R_{i^{2} } ) dy$

$R_{o} = x = \frac{y}{2}$

$R_{i} = x= (\frac{y}{2}) ^{4}$

$a=0, b=2$

$v= \int\limits^2_o {\pi } \, [(\frac{y}{2})^{2} - ((\frac{y}{2}) ^{4} )^{2} ) dy$

$v= \pi \int\limits^2_o= [\frac{y^{2} }{4} - \frac{y^{8} }{2^{8} }} ] dy$

$v= \pi [\int\limits^2_o {\frac{y^{2} }{4} } \, dy - \int\limits^2_o {\frac{y}{2^{8} } ^{8} } \, dy ]$

$v=\pi [\frac{1}{4} \frac{y^{3} }{3} \int\limits^2_0 - \frac{1}{2^{8} } \frac{y^{g} }{g} \int\limits^2_o\\v= \pi [\frac{1}{12} (2^{3} -0)-\frac{1}{2^{8}*9 } (2^{g} -0)]\\v= \pi [\frac{2}{3} -\frac{2}{g} ]\\v= \frac{4}{g} \pi$

A similar question about finding the volume generated by a given region is answered here: brainly.com/question/3455095

6 0

2 years ago

Suppose a room is 5.2 m long by 4.3m wide and 2.9 m high and has an air conditioner that exchanges air at a rate of 1200 L/min.

Readme [11.4K]

Answer:

54 minutes

Step-by-step explanation:

From the question, we are given;

A room with dimensions 5.2 m by 4.3 m by 2.9 m
The exchange air rate is 1200 L/min

We are required to determine the time taken to exchange the air in the room;

First we are going to determine the volume of the room;

Volume of the room = length × width × height

= 5.2 m × 4.3 m × 2.9 m

= 64.844 m³

Then we should know, that 1 m³ = 1000 L

Therefore, we can convert the volume of the room into L

= 64.844 m³ × 1000 L

= 64,844 L

But, the rate is 1200 L/min

Thus, time = Volume ÷ rate

= 64,844 L ÷ 1200 L/min

= 54.0367 minutes

= 54 minutes

Therefore, it would take approximately 54 minutes

4 0

3 years ago

If P = 2l + 2w, the formula to find w is .<br> If P is 30 units and l is 10 units, w is units.

Helen [10]

Answer:

<u>If P is 30 units and l is 10 units, w is 5 units</u>

Step-by-step explanation:

1. Let's check the information given to resolve the question:

P = 2l + 2w

If P is 30 units and l is 10 units, w is units

2. Replacing with the values:

P = 2l + 2w

30 = 2 (10) + 2w

30 = 20 + 2w

-2w = 20 -30 (Subtracting 2w and - 30 to both sides)

-2w = - 10

2w = 10 (Multiplying by - 1 at both sides)

<u>w = 5 (Dividing by 2 at both sides)</u>

<u>If P is 30 units and l is 10 units, w is 5 units</u>

<u>Note: Same answer than question 13938258</u>

4 0

4 years ago