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Oksi-84 [34.3K]
3 years ago
14

Need the answer ASAP

Mathematics
1 answer:
V125BC [204]3 years ago
4 0

Answer:

Approximately 201 squared inches.

Step-by-step explanation:

So, the composite figure is made up of a square and a semi-circle. The square has side lengths of 12 and the semi-circle has a radius of 6.

The total area of the figure would be the area of the square plus the area of the semi-circle. Thus, find the area of each individual figure.

Square:

The area of a square is given by:

A=l^2

Where l is the side length.

Substitute 12 for l:

A=(12)^2\\A=144\text{ in}^2

So the square is 144 square inches.

Semi-circle:

The area of a semi-circle is given by:

A=\frac{1}{2}\pi r^2

Substitute 6 for r and 3.14 for π:

A=\frac{1}{2}(3.14)(6)^2\\ A=56.52

Therefore, the total area is:

TA=144+56.52\\TA=200.52\text{ in}^2\approx201\text{ in}^2

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Answer:

2x - 10 = 44 + 8x

7x - 4 = 20 =3x

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Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    2*x-10-(44+8*x)=0

Pull out like factors :

  -6x - 54  =   -6 • (x + 9)

  -6   =  0

 Solve  :    x+9 = 0

Subtract  9  from both sides of the equation :

                     x = -9

x = -9

Move all terms containing

x

to the left side of the equation.

4

x

−

4

=

20

Move all terms not containing

x

to the right side of the equation.

4

x

=

24

divide each term by 4

x = 6

2(x−3)=−20

Step 1: Simplify both sides of the equation.

2(x−3)=−20

2x−6=−20

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2x−6+6=−20+6

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2x

2

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−4x

−4

=

12

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4 0
3 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
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The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

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brainly.com/question/1392973

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