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Ray Of Light [21]

3 years ago

13

recommend an element use to fill bottles that contain ancient paper. the element should be a gas at room temperature, should be

denser than helium, and should not easily react with other elements. Help please hurry

1 answer:

yulyashka [42]3 years ago

3 0

<span>Neon is heavier than helium and does not react with other elements. This is because Neon is a noble gas and is very stable because its outer electrons are filled.</span>

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Solve for the unknown angle

Naya [18.7K]

Answer:

(?)=70

Step-by-step explanation:

8 0

2 years ago

Which expression is equivalent to (81x4y16)12 for all positive values of x and y?<br> 40.5x4y16

IrinaVladis [17]

Answer:

$(81x^4y^{16})^{\frac{1}{2}} = 9 x^2 y^8$

Step-by-step explanation:

Given

$(81x^4y^{16})^{\frac{1}{2}}$

Required

Determine an equivalent expression

Express 81 as $9^2$

$(9^2x^4y^{16})^{\frac{1}{2}}$

Apply law of indices

$9^2^{\frac{1}{2}} * x^4^{\frac{1}{2}} * y^{16}^{\frac{1}{2}}$

$9^{\frac{2*1}{2}} * x^{\frac{4*1}{2}} * y^{\frac{16*1}{2}}$

$9^{\frac{2}{2}} * x^{\frac{4}{2}} * y^{\frac{16}{2}}$

$9^1 * x^2 * y^8$

$9 * x^2 * y^8$

$9 x^2 y^8$

Hence:

$(81x^4y^{16})^{\frac{1}{2}} = 9 x^2 y^8$

4 0

2 years ago

A submarine travels 6.6 km due West from its base and then turns and travels due South for 3.9

geniusboy [140]

Answer:

$7.7$ km

Step-by-step explanation:

The submarine's path from its base forms a right triangle when its final position is "connected" to the base. We know that the right triangle has legs of $6.6$ km and $3.9$ km, and we need to find the length of its hypotenuse. To do so, we can use the Pythagorean Theorem, which states that in a right triangle, $a^{2}+b^{2} =c^{2}$ , where $a$ and $b$ are the lengths of the triangle's legs and $c$ is the length of the triangle's hypotenuse. In this case, we know what $a$ and $b$ are, and we need to solve for c, so after substituting the given values of $a$ and $b$ into $a^{2}+b^{2} =c^{2}$ to solve for c, we get:

$a^{2}+b^{2} =c^{2}$

$6.6^{2} +3.9^{2} =c^{2}$ (Substitute $a=6.6$ and $b=3.9$ into the equation)

$43.56+15.21=c^{2}$ (Evaluate the squares on the LHS)

$58.77=c^{2}$ (Simplify the LHS)

$c^{2}=58.77$ (Symmetric Property of Equality)

$\sqrt{c^{2} } =\sqrt{58.77}$ (Take the square root of both sides of the equation)

$c=7.7,c=-7.7$ (Simplify)

$c=-7.7$ is an extraneous solution because you can't have negative distance, if that makes sense, so therefore, the submarine is approximately $7.7$ km away from its base. Hope this helps!

7 0

3 years ago

Planes X and Y and points J, K, L, M, and N are shown. Exactly how many planes contain points J, K, and N? 0 1 2 3

defon

0, because 3 points make a line.

7 0

3 years ago

Read 2 more answers

A fish was swimming 2 ½ feet below the water's surface at 1:00 pm. Three hours later, the fish was at a depth that is 3 ¼ feet b

IgorC [24]

Answer:

The fish will be at a distance of 5 3/4 ft from the water surface at 4:00 pm

Step-by-step explanation:

Here, we want to find a rational number that represents the position of the Fish at 4pm

Initially it was at a depth of 2 1/2 ft below the water surface

At 4pm, it went 3 1/4 ft further

Thus, its position with respect to the water surface at 4 pm will be;

2 1/2 + 3 1/4

= 5/2 + 13/4 = (10 + 13)/4 = 23/4 = 5 3/4 ft

6 0

3 years ago