Answer:
=>1
=> 
=> Simplify:minus and minus simplify each other and so do 3 and 3
=> So were are left with 1
Thus,the answer is 1
Step-by-step explanation:
C. 2/3; reduction
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Extraneous solutions, is answers that we get because of squaring both sides of the radical equation, but in reality, they are not going to be the solutions of the given equation.
(√(4x+41))²=(x+5)²
4x+41=x²+10x+25
x²+6x-16=0
(x-2)(x+8)=0
x1=2 , x2=-8,
And now we must to check them by substitution into initial equation
√(4x+41)=x+5
1) x=2, √(4*2+41)=2+5, √49=7, 7=7 true
2) x=-8, √(4*(-8)+41)=-8+5, √9 =-3 false,
so an extraneous solution x=-8
Answer:
Step-by-step explanation:
Combine real terms and combine complex terms
1) 3 + 2i + 2 - 5i = 3 +2 + 2i - 5i
= 5 + (2-5)i
= 5 + (-3)i
= 5 - 3i
3) 2 - (1 - 2i) + (4 -5i ) - (1 - 3i) = 2 -1 + 2i + 4 - 5i - 1 + 3i
{- is distributed to (1 - 2i) & - is distributed to (1- 3i)}
= 2 - 1 + 4 + 1 + 2i - 5i + 3i
= 6 +0i = 6
5) 4 - 3i + 4 + 3i = 4 +4 -3i + 3i
= 8
7) (3 - 2i)² + (3 +2i) = 3² - 2*3*2i + (2i)² + 3 + 2i {(a - b)² = a² - 2ab +b²}
= 9 -12i + 4i² + 3 + 2i
= 9 - 12i + 4*(-1) + 3 + 2i {i² = -1}
= 9 +3 - 4 - 12i +2i
= 8 - 10i

Answer:
The correct answers is A
Step-by-step explanation:
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