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3 years ago

Solve for the unknown angle

Mathematics

1 answer:

Naya [18.7K]3 years ago

8 0

Answer:

(?)=70

Step-by-step explanation:

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Please help me on this

Gre4nikov [31]

Answer: option a.

Step-by-step explanation:

Given the expression $\sqrt{8^{17}}$ , you need to remember:

The Product of powers property:

$a^m*a^n=a^{(m+n)}$

The Power of a power property:

$(a^m)^n=a^{mn}$

And:

$\sqrt[n]{a^n}=a$

Therefore, as the index of the radical is 2, you can rewrite $8^{17}$ as:

$8^{17}=8^{16}*8$

Rewrite this and simplify. Then:

$=\sqrt{8^{17}}$

$=\sqrt{8^{16}*8}=\sqrt{8^{16}}\sqrt{8}=\sqrt{(8^{8})^2}\sqrt{8}=8^8\sqrt{8}$

This matches with the option a.

3 0

3 years ago

The actual height of a book is 914 inches. Beverly estimates the height of the book and finds her percent error to be less than

s2008m [1.1K]

Answer: 8.88 inches & 9.62 inches

Step-by-step explanation:

i took the test

6 0

2 years ago

Find three consecutive odd integers with a sum of 63

grin007 [14]

Answer:

19, 21, and 23.

Step-by-step explanation:

4 0

3 years ago

A fish tank, in a shape of rectangular prism, measures

murzikaleks [220]

Answer:

The deep of the water would be 20 cm

Step-by-step explanation:

step 1

Find the volume of the water

The volume of the water is equal to

$V=LWH$

we have

$L=60\ cm\\W=40\ cm\\H=50/ cm$

substitute

$V=(60)(40)(50)$

$V=120,000\ cm^3$

step 2

Find the deep of the water, if the tank is returned to its horizontal position

(resting on its 60 cm × 100 cm base)

Now we have

$L=60\ cm\\W=100\ cm\\H=?\ cm$

$V=120,000\ cm^3$

substitute the given values

$120,000=(60)(100)H$

solve for H

$H=120,000/6,000$

$H=20\ cm$

therefore

The deep of the water would be 20 cm

5 0

3 years ago

HELP HELP HELP, IS IT CORRECT, ILL MARK YOU BRAINIEST - THANKYOU

Alla [95]

Answer:

$48\pi$

Step-by-step explanation:

Volume =

$r ^{2} \times \pi \times h = 4 ^{2} \times \pi \times 3 = 48\pi$

r=4

h=3

7 0

3 years ago