Question

Find two consecutive whole numbers such that 4/7 of the larger exceeds 1/2 of the smaller by 5

Answer 1

Answer:

The consecutive numbers are 62 and 63

Step-by-step explanation:

Let the larger number be represented by x and the smaller number by y,

Provided they are consecutive numbers;

$x = y + 1$ --- Equation 1

From the question; we have that

$\frac{4x}{7} = \frac{y}{2} + 5$ --- Equation 2

Required

Find x and y

Multiply both sides of equation 2 by 14

$14 * \frac{4x}{7} = 14 * \frac{y}{2} + 14 * 5$

$2 * 4x = 7 * y + 70$

$8x = 7y + 70$ ---- Equation 3

Substitute y + 1 for x in equation 2

$8(y + 1) = 7y + 70$

Open bracket

$8y + 8 = 7y + 70$

Collect like terms

$8y - 7y = 70 - 8$

$y = 62$

$x = y + 1$

So,

$x = 62 + 1$

$x = 63$

Hence, the consecutive numbers are 62 and 63