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storchak [24]
3 years ago
12

If a couple were planning to have three​ children, the sample space summarizing the gender outcomes would​ be: bbb,​ bbg, bgb,​

bgg, gbb,​ gbg, ggb, ggg. a. Construct a similar sample space for the possible health outcomes​ (using h for healthy and s for sick​) of two children. b. Assuming that the outcomes listed in part​ (a) were equally​ likely, find the probability of getting two healthy children. c. Find the probability of getting exactly one healthy child and one sick child. a. What is the sample​ space?
Mathematics
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

a.S={hh,sh,hs,ss}

b.tex]\frac{1}{4}[/tex]

c.\frac{1}{2}

Step-by-step explanation:

We are given that a sample space of three children

S={bbb,bbg,bgb,bgg,gbb,gbg,ggb,ggg}

a.We have to construct similar space for two children where h for healthy and s for sick.

Then the sample space of two children

S={hh,sh,hs,ss}

b.Number of cases favorable to two healthy children=1

Total number of  cases=4

Number of cases for two healthy children=1

Probability =Number of favorable cases divided  by total number of cases

Probability=\frac{1}{4}

Hence, the probability of getting two healthy children=\frac{1}{4}

c.We have to find the probability of getting exactly one healthy child and one sick child

Number of cases of one healthy child and one sick child={hs,sh}=2

Probability=\frac{2}{4}=\frac{1}{2}

Hence, the probability of getting exactly one healthy child and one sick child=\frac{1}{2}

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The probability of getting a total of 8 when two dice are rolled is 0.139.

Probability is a number that expresses the likelihood or chance that a specific event will take place. Probabilities can be represented by proportions on a 0–1 scale.

A single die will have six sides with the numbers: 1, 2, 3, 4, 5, and 6. Each of these events is equally likely to occur if the dice are rolled fairly. So the probability of getting any side of the number is 1/6. Therefore, the probability of getting 1 in dice is 1/6, 2 is 1/6, and so on.

Therefore, the total possible outcomes are the multiplication of the total possible outcomes on dice 1 and dice 2, which is 36.

This possible outcome of rolling two dice is given by,

\left\{\begin{array}{ccccccc}(1, 1)&(1, 2)& (1, 3)&(1, 4)&(1, 5)&(1, 6)\\(2, 1)&(2, 2)&(2, 3)&(2, 4)&(2, 5)&(2, 6)\\(3, 1)&(3, 2)&(3, 3)&(3, 4)&(3, 5)&(3, 6)\\(4, 1)&(4, 2)&(4, 3)&(4, 4)&(4, 5)&(4, 6)\\(5, 1)&(5, 2)&(5, 3)&(5, 4)&(5, 5)&(5, 6)\\(6, 1)&(6, 2)&(6, 3)&(6, 4)&(6, 5)&(6, 6)\end{array}\right\}

The probability of getting a total of 8 from both dice is given by, (2, 6) (3, 5) (4, 4) (5, 3) (6, 2). So the number of favorable outcomes is 5 and the total outcome is 36. The probability is P(getting a total of 8 from both dices)=5/36= 0.139.

The answer is 0.139.

The complete question is -

Consider rolling dice and getting a total of 8. Find the probability of two dice are rolled. (Enter the value of probability in decimals. Round the answer to three decimal places).

To know more about dice probability:

brainly.com/question/17239706

#SPJ4

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