Answer:
The area of the paralellogram is 24 square units.
Step-by-step explanation:
Geometrically speaking, the area of the parallelogram has an equation equivalent to the area formula for a rectangle, that is:
(1)
Where:
- Area.
- Base.
- Height.
The base and height of the parallelogram are, respectively:
Base


Height


Then, the area of the parallelogram is:


The area of the paralellogram is 24 square units.
The vertex is (0,-8)
im not sure about axis of symmetry but i don’t think it has one
<span><span>n<span>x4/</span></span>5</span>=<span>3/<span>4
</span></span><span><span><span><span>1/5</span><span>n<span>x^4</span></span></span><span><span>x^4/</span>5</span></span>=<span><span>3/4</span><span><span>x^4/</span>5</span></span></span><span>
Answer is n=<span>15/<span>4<span>x<span>4</span></span></span></span></span>
So what we do is
area that remains=total area-triangle area that was cut out
we need to find 2 things
total area
triangle area
total area=rectange=base times height
area=(3x+4) times (2x+3)
FOIL or distribute
6x^2+8x+9x+12=6x^2+17x+12
triangle area=1/2 times base times height
triangle area=1/2 times (2x+2) times (x-2)=
(x+2) times (x-2)=x^2+2x-2x-4=x^2-4
so
total area=6x^2+17x+12
triangle area=x^2-4
subtract
area that remains=total area-triangle area that was cut out
area that remains=6x^2+17x+12-(x^2-4)=
6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
5x^2+17x+16
area that remains is 5x^2+17x+16
Answer:
I hate maths it's a boring subject