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Assoli18 [71]
3 years ago
14

Evaluate these questions 3a+2a= c+d there is a line under this one ad

Mathematics
2 answers:
dezoksy [38]3 years ago
5 0
Greetings!

1)
For this question we can combine the terms together as they are like:
3a+2a
Combine like terms.
=5a


Hope this helps.
-Benjamin


WINSTONCH [101]3 years ago
4 0
Get photo math it would help you out with all of your math problems
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ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions
77julia77 [94]

Answer:

C. It has been stretched horizontally.

Step-by-step explanation:

According to the diagram, the parabola has not been reflected in any way, nor has it been translated, since the parabola is pointing up in a smile, and the vertex is still at the origin.

The parabola does appear to be stretched, since the parent function had points at (1, 1), and (2, 4), but this parabola does not contain those points.

Since the parabola appears to be flatter than the parent function, we can say that C. It has been stretched horizontally.

Hope this helps!

3 0
4 years ago
Read 2 more answers
Solve the equation for x.<br> 1/3 (6x - 15) = 1/2 (10x-4)
Readme [11.4K]

Answer:

<h2>x = - 1</h2>

Step-by-step explanation:

\frac{1}{3} (6x - 15) =  \frac{1}{2} (10x - 4)

Expand the terms in the bracket

That's

\frac{1 }{3}  \times 6x  +   \frac{1}{3} ( - 15) =  \frac{1}{2} (10x)   +  \frac{1}{2} ( - 4) \\ 2x - 5 = 5x - 2

<u>Subtract 5x from both sides</u>

2x  - 5x - 5 = 5x - 5x - 2  \\  - 3x - 5 =  - 2

<u>Add 5 to both sides</u>

- 3x - 5 + 5 =  - 2 + 5 \\  - 3x = 3

<u>Divide both sides by - 3</u>

\frac{ - 3x}{ - 3}  =  \frac{3}{ - 3}

We have the final answer as

<h3>x = - 1</h3>

Hope this helps you

3 0
3 years ago
Polar form of (x+6)^2 +y^2=36
Sindrei [870]

Answer:

  r = -12cos(θ)

Step-by-step explanation:

The usual translation can be used:

  • x = r·cos(θ)
  • y = r·sin(θ)

Putting these relationships into the formula, we have ...

  (r·cos(θ) +6)² +(r·sin(θ))² = 36

  r²·cos(θ)² +12r·cos(θ) +36 +r²·sin(θ)² = 36

  r² +12r·cos(θ) = 0 . . . . subtract 36, use the trig identity cos²+sin²=1

  r(r +12cos(θ)) = 0

This has two solutions for r:

  r = 0 . . . . . . . . a point at the origin

  r = -12cos(θ) . . . the circle of interest

4 0
4 years ago
Factoring Trinomials (<br> Factor each completely.<br> 1) 3p² – 2p - 5
Maurinko [17]
3p^2 - 2p - 5
3p^2 -5p+3p-5 (5 times 3 equals 15)
p(3p-5) +1(3p-5)
Answer:
(3p - 5)(p + 1)
8 0
3 years ago
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I need help with this problem for my class! thanks
PSYCHO15rus [73]

Answer:

point on line= (0,8)

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7 0
3 years ago
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