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yarga [219]
3 years ago
10

Solve the following problem.

Mathematics
1 answer:
DaniilM [7]3 years ago
7 0
<span>19,200 units --------------------------------at a total cost of $67,585.06
therefore  one unit

</span>67,585.06/19200=$3.5200552 

the answer is the letter <span>D. 3.52
</span>
the cost per unit is $3.52
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Mariulka [41]

Answer:

3 is the answer

Step-by-step explanation:

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An official playing field (including end zones) for the Indoor Football League has a length 29 yd longer than its width. The per
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An official playing field (including end zones) for the Indoor Football League has a length 29 yd longer than its width. The perimeter of the rectangular field is 158 yd. Find the length and width of the field

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What is 45 X45?////////////////
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3 years ago
Graph the solution to this system of inequalities in the coordinate plane.
Vsevolod [243]

By using Geogebra online graphing calculator, the solution to this system of inequalities are plotted in the image attached below.

<h3>What is an inequality?</h3>

An inequality is a mathematical relation that compares two (2) or more integers and variables in an equation based on any of the following:

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3 0
2 years ago
A fish was swimming LaTeX: 2\frac{1}{2}2 1 2 feet below the water's surface at 1:00 p.M. Three hours later, the fish was at a de
marin [14]

Answer:

\frac{23}{4} feet

Step-by-step explanation:

The depth of the fish to the surface of water at 1:00 pm = 2 \frac{1}{2} feet

                                                                             =   \frac{5}{2} feet

The depth of the fish to its initial position at 4:00 pm = 3 \frac{1}{4} feet

                                                                              = \frac{13}{4} feet

The position of the fish with respect to the water's surface at 4:00 pm = the depth of the fish to the surface of water at 1:00 pm + the depth of the fish to its initial position at 4:00 pm

                                        =  \frac{5}{2} + \frac{13}{4}

                                        = \frac{10 + 13}{4}

                                         = \frac{23}{4}

The position of the fish with respect to the water's surface at 4:00 pm is \frac{23}{4} feet.

8 0
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