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Vaselesa [24]
4 years ago
6

For a particular pickup truck the percent markup is known to be 115% based on cost to the seller. If the seller paid $15,800 for

the truck, what would be the percent markup be based on the sale price? (Round to the nearest tenth percent)
Mathematics
1 answer:
nexus9112 [7]4 years ago
8 0

Answer:

115%(15,800)= $18,170. <--- markup price

$15,800+$18,170= $33,970 total price

That is 115% x $15,800 = $18,170 markup price

Then add the original price to the markup price

That is $15,800 + $18,170 = $33,970

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So what times .2 equals 20
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6 0
4 years ago
Read 2 more answers
Write and solve a proportion to answer the question. (Skills Review Handbook) 22. 30 is 15% of what number?
algol13

Answer:

The answer is 148.6666667

Step-by-step explanation:

1) Set a linear quation

\frac{22.30}{x}  =  \frac{15}{100}

2) Cross multiply

15x = 22.30 \times 100

3) Multiple the right side

15x = 2230

4) Divide both side by 15

\frac{15x}{15}  =  \frac{2230}{15}

5) Solve the linear equation

x = 148.6666667

3 0
3 years ago
I need to know the distance between points x and y
USPshnik [31]

Answer:

Step-by-step explanation:

Distance between two points P(x1,y1) and Q(x2,y2) is given by: d(P, Q) = √ (x2 − x1)2 + (y2 − y1)2 {Distance formula} 2. Distance of a point P(x, y) from the origin is given by d(0,P) = √ x2 + y2.

8 0
3 years ago
The National Academies of Sciences Engineering, and Medicine
snow_tiger [21]

<em>Greetings from Brasil...</em>

According to the annex, we note that

1 qt = 1 quart = 0.95L

To solve this problem, just apply some rules of 3.....

1st - how many qt's are in 15.5 cups

  qt                 cup

   1   ----------     4

   X  ----------   15.5

4 · X = 1 · 15.5

4X = 15.5

X = 15.5 ÷ 4

X = 3.875qt

Last rule of 3 to know how many liters there are in 3.875qt:

  qt                       litres

   1         ----------    0.95

3.875    ----------      Y

1 · Y = 0.95 · 3.875

<h2>Y = 3.68L</h2>

In a day a young man should drink 3.68L of water

6 0
3 years ago
On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)
xz_007 [3.2K]

Answer:

P = 10 + 2\sqrt{53} units

Step-by-step explanation:

Given

Shape: Kite WXYZ

W (-3, 3),  X (2, 3),

Y (4, -4),  Z (-3, -2)

Required

Determine perimeter of the kite

First, we need to determine lengths of sides WX, XY, YZ and ZW using distance formula;

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

For WX:

(x_1, y_1)\ (x_2,y_2) = (-3, 3),\ (2, 3)

WX = \sqrt{(-3 - 2)^2 + (3 - 3)^2}

WX = \sqrt{(-5)^2 + (0)^2}

WX = \sqrt{25}

WX = 5

For XY:

(x_1, y_1)\ (x_2,y_2) = (2, 3)\ (4,-4)

XY = \sqrt{(2 - 4)^2 + (3 - (-4))^2}

XY = \sqrt{-2^2 + (3 +4)^2}

XY = \sqrt{-2^2 + 7^2}

XY = \sqrt{4 + 49}

XY = \sqrt{53}

For YZ:

(x_1, y_1)\ (x_2,y_2) = (4,-4)\ (-3, -2)

YZ = \sqrt{(4 - (-3))^2 + (-4 - (-2))^2}

YZ = \sqrt{(4 +3)^2 + (-4 +2)^2}

YZ = \sqrt{7^2 + (-2)^2}

YZ = \sqrt{49 + 4}

YZ = \sqrt{53}

For ZW:

(x_1, y_1)\ (x_2,y_2) = (-3, -2)\ (-3, 3)

ZW = \sqrt{(-3 - (-3))^2 + (-2 - 3)^2}

ZW = \sqrt{(-3 +3)^2 + (-2 - 3)^2}

ZW = \sqrt{0^2 + (-5)^2}

ZW = \sqrt{0 + 25}

ZW = \sqrt{25}

ZW = 5

The Perimeter (P) is as follows:

P = WX + XY + YZ + ZW

P = 5 + \sqrt{53} + \sqrt{53} + 5

P = 5 + 5 + \sqrt{53} + \sqrt{53}

P = 10 + 2\sqrt{53} units

6 0
4 years ago
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